quadratic functions
Elimination
Substitution
Random
find the X
100
A takes 6 days less than B to finish a piece of work. If both A and B together can finish the work in 4 days, find the time taken by B to finish the work.
12 days
100
2x + y = 1
−3x + y = 2
Solve using elimination method
-1/5,7/5
100
Solve using substitution method: x + y = 5 and 3x + y = 11.
x = 3, y = 2
100
2x2-2x-24=0
x=4,-3
100
If k =3 and (x-2)/4 = k, then find the value of x.
14
200
The product of two successive integral multiples of 5 is 300. Then the numbers are:
15,20
200
−2x + 3y = −1
2x + 5y = 25
Solve using elimination
(5,3)
200
Solve the simultaneous equations: 3a + 4b = 43 and -2a + 3b = 11
a = 5, b = 7
200
x2+10x+16
(x+2)(x+8)
200
Solve for m and n, if 5m-2n=17 and 3m+n=8.
m=3 n= -1
300
The sum of two numbers is 27 and product is 182. The numbers are:
13 and 14
300
4x + 2y = 14
5x + 2y = 16
Solve using elimination
(2,3)
300
The method of solving a variable in the equation of another variable and then substituting the value of the first variable into another equation is called:
Substitution
300
4x2+15x+9=0
x=-3/4,-3
300
Solve the simultaneous equations: x - y = 6 and x - 4y = 3
x = 7, y = 1
400
Nature of the roots of quadratic equation, depends on:
discriminant
400
x – y = −6
x + y = 8
Solve using elimination
(1,7)
400
Solve: 2x + 13y = 36 and 13x + 2y = 69
x = 5, y = 2
400
6x2-x-40=0
x=8/3,-5/2
400
wo simultaneous equations are given as 2x + y = 5 and 3x + y = 7. The value of x is equal to
2
500
2x2-11x+14=0
7/2,2
500
2x+3y=15
x-3y=3
Solve using Elimination
(6,1)
500
Solve the given pair of equations by substitution method:
x+y=11
x−y=−3
(4,7)
500
2x2+13x+15=0
x=-3/2,-5
500
If 5x + y = 20 and 10x - 2y = 50 are two linear equations in two variables. Find the value of x and y.
x = 9/2, y = -5/2