Problems & dieletric
Resistors
Capacitors
J=oE
Problems
100

You need a capacitance of 50uF, but you don’t happen to have a  50uF capacitor. You do have a 75uF capacitor. What additional capacitor do you need to produce a total capacitance of 50uF? Should you join the two capacitors in parallel or in series?

Series

100

What does a resistor do?

A resistor limits the flow of current.

100

What does a capacitor do?

Stores charge

100

Give an inequality for the current. 

(Assume same diameter, length, material for each wire)

I= I4 > I2 = I3

100

Find the Resistance Equivalence from point 1 to point 2 

Req = 54.5


Req = ((1/300) + (1/200) + (1/100))^-1

200

You need a capacitance of 50uF, but you don’t happen to have a 50uF capacitor. You do have a 30uF capacitor. What additional capacitor do you need to produce a total capacitance of 50uF. Should you join the two capacitors in parallel or in series?

Parrallel, 20uF

200

How does adding resistors in series affect the resistance equivalence?

Increases the resistance equivalence

200

How does adding capacitors in parallel affect the capacitance equivalence?

Increases the capacitance equivalence 

200

Same material, but different diameters

How does I1 compare to I2?

I= I1

200

What is the magnitude and direction of the current across the resistor?

I1 = .9A 

To the left

300

A 2.0-cm-diameter parallel-plate capacitor with a spacing of 0.50 mm is charged to 200 V. What are (a) the total energy stored in the electric field and (b) the energy density?

a) 1.1*10^-7 J

b) .71/m^3

300

How does adding resistors in parallel affect the resistance equivalence?

Decreases the resistance equivalence 

300

How does adding capacitors in series affect the capacitance equivalence?

Decreases the capacitance equivalence 

300

Same material, but different diameters

Compare the drift speed in each segment

Vd1 >Vd2,


(J=nevd, since J1 > J2 )


300

Rank the I (current)

Assume all resistors have the same resistance

Ip >I= It > Iq = I


400

Two 4.0cm x 4.0cm metal plates are separated by a 0.20-mm-thick piece of Teflon. (k=2.1)

A) What is the capacitance?

A) .15nF


400

Rank the brightness(Current) of each lightbulb.

Assume each light bulb has the same resistance, and each battery provides the same voltage.

A = B = C
400

Where is the energy stored in a capacitor?

The energy is stored in the electric field

400

Rank the resistance for each wire
(Same material )

Take your time 

R4 > R1 = R5 > R3 >R

(Depends on area and length)

400

Find the resistance equivalnce across point a to point b

Rab = 2 + 2 + 3 = 7

500

Two electrodes are held 0.10 mm apart and are attached to a 9.0 V battery. Without disconnecting the battery, a 0.10-mm-thick sheet of Mylar (k=3.1) is inserted between the electrodes. What are the capacitor’s potential difference, electric field, and charge (a) before and (b) after the Mylar is inserted?

a) Q = 20pC, E = 90kV/m

b) Q = 62pC 

500

What is the Resistance of the second resistor for each wire to the same current?

R2 =2R1

Use Kirchhoff's laws :)

500
Trying to increase the amount of charge in a circuit, you have to decide how to add your new capacitor. Would you add it in parallel or in series to your circuit?

To increase the charge in your circuit, add the capacitor in parallel.

500

The two segments of the wire have equal diameters but different conductivities. Current passes through this wire. If the conductivities have the ratio (Conductivity2/Conductivity1) = 2. What is the ratio of the electric field strengths in the two segments of the wire?

E2 / E1 = (1/2)

(J1=J2)

(o1E1=o2E2)

500

What is the magnitude and direction of the current in the bottom wire?Hint:(Set up loops and junction law)

I = .4A

to the right