The Derivative Function
Derivatives of Polynomials
Quotient Rule
Chain Rule
100
Given: f(x)=1/(x-1) Find: f'(0)
-1
100
Apply differentiation rules to determine the derivative of the function: y = root(x)-3 root(x+1)
1/(2 root x) - 3/(2 root(x+1))
100
Determine the slope of the tangent line at x = 7: f(x) = (x + x-1)(x + x-2)
1/2
100
Given f(x) = 3x + 1 and g(x) = x2 -3 determine: g(f(x))
9x2+6x-2
200

Determine dy/dx (must show your full solution for points) y=(x+3)2

1/(2 root(x-8))

200
Determine the equation of the tangent line at x = 1: f(x) = 7x3 - 3x-2
y = 27x - 23
200

Determine the equation of a line that is perpendicular to the tangent at x = 0: f(x) = 1/3 x3 - 1/2 x2

x = 0

200
Determine f'(x): f(x) = 1/(x2 + 1)3
-6/(x2 + 1)4
300

Determine the slope of a line perpendicular to the tangent line at the given x value. f(x) = 1/x at x = 3

9

300

Determine the slope of a line perpendicular to the tangent line at x = -1. f(x) = -(x+7x2)

-1/13

300

Determine the equation of a line perpendicular to the graph of y = (x+1)(x2 + 4x + 1) at (0, 1)

x + 5y - 5 = 0

300
Differentiate f(x) = x3(2 - 5x3)3
3x2(2 - 5x3)3+x33(2 - 5x3)2(-15x2)
400

Determine the equation of a line that is perpendicular to the tangent line at the given x-value: f(x) = x2+3x-6 at x = 2

y = -1/7x + 30/7

400

Determine the equation of a line that is perpendicular to the tangent line at x = -1. f(x) = (2x-1 - 7)2

y = -1/36x + 2915/36

400
For what value(s) of x is the slope of the tangent line to y = (2x + 1)3 negative?
none
400
Determine the slope of the tangent when x = 1: y = 1/(1 + x)2
-1/4
500
Determine the value(s) of x for which each of the following functions has a horizontal tangent line. f(x) = x3 - 3x
x = 1, x = -1
500
For what values of x do the following pair of graphs have tangent lines with the same slope? f(x) = x2 - 3x g(x) = 1/x
x = -1/2 and x = 1
500
For what value(s) of x do the tangents to y = x2 and y = x(x2 - 1) have the same slope?
x = -1/3, x = 1
500
Determine the points on the graph of each function where the slope of the tangent is 0. f(x) = (1 - x)/x2
(2, -1/4)