y=(2x+1)2
y'=4(x+1)
f(x)= x(x+1)3
Find f'(x) (fully factorise me!)
Differentiate
y=x/(x+1)
1/(x+1)2
Find the third derivative of x3-x2+x-1
6
Differentiate 4x2+(4/x2)
8x-8/x3
Find y'(3) when y=10(x2-3)6
22799360
f(x)=(x-2)3(x+1)5
f'(x)=?
f'(x)=4(x-2)2(x+4)4(2x-3)
Find f''(x) when f(x)=x/(x+1)
-2/(x+1)3
Find the fourth derivative of 2x3+x
0
Find the values of x for which y''=0 given that,
y=x4-6x2+11
x=1,-1
Find f'(x) when f(x)=(1-4x)2
-8(1-4x)
or 32x-8
f(x)= x1/2(x+3)2
Find f'(4).
f'(4)=129/4 or 32.25
Find the stationary point for y=12/(2x+5)2
Tricked ya! No stat points here
Find the fourth derivative of:
y=1/x
24/x5
Differentiate y=2xe-x
2e-x-2xe-x
f(x)= 1/(x+2)
f'(x)= -1/(x+2)2
f(x)=3x2(2x3-3x2)
f'(x)=6x5+3x4-18x3
Differentiate (x2+1)/ex
−(x2−2x+1)e−x
Find the fourth derivative of x1/3
-10x-8/3 /27
Find where f''(x)=0
y=x4+4x3+6x2+3x+2
(-1,2)
Find f'(-1) when f(x)=1/(4-3x)2
6/343
Find the second derivative:
y=4x3(x5+2x2)
224x6+160x3
Differentiate: (x-1)2/(2x+5)
(2x+5)(x-1)(3-x)/(2x+5)2
Find the 6th derivative of x10
151200x4
It is given that y = ƒ(g(x)), where ƒ(1) = 3, ƒ′(1) = −4, g(5) = 1 and g′(5) = 2. What is the value of y′ at x = 5?
-8