Thevenin Equivalent Circuits
Norton Equivalent Circuits
Op Amps
100

Draw the thevenin equivalent circuit assuming R1=5 and R2=3

Vth=6 

Rth=10

100

Find the Norton equivalents circuit between the positive and negative terminals

IN= 1A

RN = 4 ohms

100

Calculate Vo as a function of V1, V2, and V3.

Vo = -2V1 - 2V2 + (5/2)V3

200

Draw the Thevenin equivalent and compute the power dissipated in the resistor for Rl=10 ohms

Vth=18 V

Rth=10 ohms

P=10 W

200

Find the Norton equivalent between terminals a and b.

In = 0 A (an open)

Rth = 0.15 ohm

200

Solve for Vo as a function of R1, R2, R3, V1, V2, and V3.

Vo = (1+R4/R3)((R2/R1+R2)V1 + (R1/R1+R2)V2)) - (R4/R3)V3

300

Using the Thevenin equivalent circuit, find the value of Rl which dissipates the most power. How much power is dissipated? 

Vth=-1 V

Rth=68/15 = Rl

P=15/272 W
300

Find the Norton equivalent between terminals a and b.

In = 0.217 A

Rth = 9.2 ohm

300

Relate Vo to Vs.

Vo = 8.5Vs

400

Find the Thevenin equivalent of the circuit

Vth=-7.6

Rth=1.6

400

Find the maximum power that can be extracted by the load resistor. (You can use a Thevenin or Norton equivalent circuit for this.)

2.09 mW

400

Calculate Vo as a function of R1, R2, V1, V2, and V3. Then, provide values for R1 and R2 that will make Vo = -3V1 + 3V2 +V3.

Vo = (-12/R1)V1 + (1+12/R1)((6/6+R2)V2 + (R2/6+R2)V3)

R1 = 4 ohms, R2 = 2 ohms