Random 1
Motors/Generators
Random 2
Electromagnet
Random 3
100

2000V is converted to 100V

Identify the type of transformer present

Step down transformer

100

Give the term

The effect of a force that causes rotation.

Torque

100

Occurs when a current carrying conductor inside a magnetic field experiences a force.

M____________

Motor Effect
100

Which of the following represents the formula for TORQUE?

= ILB Cos Ꝋ

= nI AB Sin Ꝋ

= nI AB Sin Ꝋ

100

Which of the following is NOT a formula for acceleration?

a = F/m

a = Eq/m

a = E x m/q

a = v - u /t

a = E x m / q

200

A transformer built in a radio reduces the 240V supply voltage to 12V.

If the number of turns in the secondary coil is 100 what is the number of primary coils?

NP /NS   =  VP /VS

NP = VP x NS / VS

NP =  240 x 100 / 12

NP = 2000 turns

200

Which motor has a 

Split ring

Slip ring

Split ring = DC

Slip ring = AC

200

qE = qvB

Identify 

(q)

(E)

(B)

q = charge

E = Electric field

B = Magnetic field strength

200

When the north pole of a magnet is moved into a coil the direction of the induced current in the coil as seen from the magnet side is ______________. 


Use the right-hand rule

Anticlockwise

200

Identify the scientist who produced the first DC motor.

Michael Faraday

300

A student places a square coil of wire with a side length of 5cm in a uniform VERTICAL magnetic field of strength 0.1T.

The plane of square is at an angle of 400 to the magnetic field.

Calculate the magnetic flux.

A =  (0.05 x 0.05) = 0.0025

= 0.1 x 0.0025 Cos 40

= 1.9 x 10^-4 Wb

300

Name of the device which transforms mechanical energy into electrical energy.

Generator

300

Give the name of the law

An induced current produces magnetic fields which tend to oppose the change in magnetic flux that induces such currents.

Lenz Law

300

A uniform electric field is set up between two parallel plates 5 cm apart, with a potential difference of 120 V between the plates. 

Calculate the magnitude of the electric field.

E = V/d 

E = 120/0.05

E = 2400 V/m

300

Using the formula

B = E/v

Calculate the magnetic field strength given the electric field is 2 V/m and the velocity is 3m/s

B = 2 / 3

B = 0.67 T

400

A radio with 2000 turns in the primary coil and 100 turns in the secondary coil draws current 4A. 

What is the current in the primary coil.

IP /IS = NS /NP            

IP = NS x IS / NP

IP =  100  x 4  / 2000          

    = 0.2A 

400

Identify the part of a DC motor that changes the direction of the current every half rotation in order to keep the coil motion continuous

Split ring

400

A single square coil wire with side lengths of 5cm is free to rotate within a magnetic field with strength 1 x 10^-4 T.

A current of 1A is flowing through the coil.

ꚍ = 1 x 1 x 0.0025 x (1x10^-4) Sin 90

ꚍ = 2.5 x 10^-7 Nm

400

A conductor enters a constant magnetic field. 

Describe the conductor as it enters the loop

Describe the conductor as it exits the loop

Entry  = current has a non zero magnitude

          = generates a magnetic field that opposes 

            the change in flux  

400

Describe what happens when a bar magnet enters a conducting loop.

As the bar magnet approaches the loop, it experiences a repulsive force due to the induced emf.

Since like poles repel, the loop must behave as if it were a bar magnet with its north pole pointing up.

500

Two parallel plates are separated by 1cm. One plate is earthed the other has a potential of 5kV.

Determine the final speed of an electron (v)

v2 = 2qv / m

v2 = 2(1.6 x 10^-19  x 5 x 10^3) / 9.1 x 10^-31

v2 = 1.7 x 10^15

v = 4.2 x 107  m/s

500

Indicate how the speed of a DC motor can be controlled.

  1. By varying the supply voltage.   OR
  2. By varying the flux, and by varying the current through the field winding.           OR
  3. By varying the armature voltage, and by varying the armature resistance.
500

An electron travels with a velocity of 3400 m/s at an angle of 60° to the horizontal and enters an electric field of magnitude 1200 N/C . 

Calculate the acceleration of the electron.

F = ma = Eq

a = Eq/m

a = 1200 (1.602 x 10^-19) / 9 x 10 ^ -31

a = 2.136 x 10^14 m/s/s

500

Calculate the force on the conductor given; 

The conductor has a length of 1.2m and carries 4A at angle of 40to the magnetic field which is 2T. 

F = I x L x B x Sin (pheta)

F = 4 x 1.2 x 2 Sin (40)

F = 6.17 N

500

Calculate the work done in joules for a proton between two parallel plates that are 3m apart and experience a unform electric field of 200 V/m.

W = q x E x d

W = (1.6 x 10^-19) x 200 x 3

W = 9.6 x 10 ^-17