Helium (He) is found in what subshell
s-block
From what column do we pick our element to use in abbreviated electron configurations?
18 (last one; Noble gasses)
how many electrons can be held in ONE orbital?
2 electrons
Is this configuration possible? Why or why not?
1s² 2s² 2p⁶ 3s² 3p⁷
Not possible — p sublevel can only hold 6 electrons.
Which orbital diagram correctly represents 3p³?
A) ↑↓ ↑ _
B) ↑ ↑ ↑
C) ↑↓ _ _
b
what is the maximum amount of electrons that can be held in the F block
14 electrons
Which element would you use to abbreviate for I (iodine)
Kr (krypton)
How many orbitals are present in the D subshell?
5 orbitals
A student draws 3p⁴ as:
↑↓ ↑↓ _
What is wrong?
Electrons must fill empty orbitals before pairing.
Correct: ↑↓ ↑ ↑
Complete the orbital diagram for:
2p⁴
↑↓ ↑ ↑
When completing an electron configuration, what must you do to determine the coefficient for elements in the D block?
subtract 1 from the row number
Which element is being described?
[Kr] 5s2 4d10 5p6
Xe (xenon)
According to pauli's principle, what must you do when 2 electrons are present in the same orbital?
the electrons nust spin in opposite directions (arrows face different ways)
A student writes:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d¹⁰
Is this allowed?
If not, what’s wrong?
Incorrect order.
4s should be filled before 3d is completed.
If I am completing an abbreviated configuration for a Noble gas (last column) how is this possible?
Complete the FULL electron configuration for Y
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10
What is the abbreviated configuration for Ne (neon)?
[He] 2s2 2p6
to follow Hund's Rule, when filling orbitals, what must you do?
place electrons in separate orbitals until there must be a pairing of electrons (everyone gets their own house before a roommate)
Is this valid for 2p³?
↑ ↓ ↑
No. Hund’s Rule says electrons in singly occupied orbitals should have parallel spins before pairing.
They should all be ↑ (or all ↓).
What is the maximum number of UNPAIRED electrons that can be present in the D subshell
5
Complete the FULL electron configuration for U
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d10 6p67s2 5f4
[Rn] 7s2 5f14 6d2
Complete an orbital diagram of Flourine (F)

A student claims this configuration has 48 electrons:
[Kr] 5s² 4d¹⁰
Is this correct?
Recall: [Kr] = 36 electrons
36 + 2 + 10 = 48 electrons
This one is actually correct
write out the order of all sub levels (ie. 1s, 2s, 2p...)
1s, 2s, 2p,3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p