Mr. Chong is on life support after macro dosing Trenbolone. The machine draws 150V with a current of 80A. What is the Power of the machine? How much energy is used after 20 days of constant usage in kWhrs? If it costs ¢9 for every kWhr, how much did it cost to run the machine for 20 days?
P=150*80=12000W
12000/1000*24*20=5769kWhrs
9*5769=¢51921 or $519.21
What stays the same throughout a series circuit? Throughout a parallel circuit?
Bonus 50 pts: What happens to the current in a series circuit if I add another resistor?
Series Circuit: Current
Parallel Circuit: Voltage
Bonus: Decreases
50pts each
Watts = Joules / Second
Amps = Coulombs / Second
Volts = Joules / Coulomb
Mr. Chong has a 15Ω camera, a 9Ω electric nail gun, two teddy bears, and a dream. They are connected in parallel with a total current of 12A. Find the total voltage of the circuit.
1/R_T=1/15+1/9=8/45
R_T=45/8=5.625Ω
V=IR=12*5.625=67.5V
Mr. Chong connects a 7Ω Fork, a 10Ω Silver Spoon, and a 12Ω Metal Chopstick into a series circuit with a 20V battery because sparky boom boom. What is the voltage across the Metal Chopstick?
Find total current first.
V=IR | I=20/(7+10+12)=0.69A
Find the voltage across the resistor.
V=IR | V=0.69*12=8.3V
Draw a unicorn with candy cane pants
Your mom (villain) wears an electrically charged jacket next to the childrens hospital to mess with their electronics! Her jacket has a charge of 2C and the hospital equipment has a total average of 8C. If the hospital equipment experiences 580,000N of force, how far was she standing from the hospital?
Bonus 100pts: Was the charge repelling or attracting?
sqrt((K*2*8)/580000)=497.995
500m
Bonus: Repelling, like charges repel
Mr. Chong is using a deathray pointed at Florida! The death ray has a resistance of 120Ω and requires a current of 5A. The Florida Coast Guard calculated that 54,000 J of energy was released. How long was the deathray activated for?
P=I^2R=5^2*120=3000W
P=J/t
3000=54000/t
t=18s
Two charged objects exert a force of 1.38N on each other. If the charge of one object is tripled and the distance is divided in half, find the magnitude of the new force.
F_(old)=(k*q_1*q_2)/r^2=1.38N
F_("new")=(k*3q_1*q_2)/((1/2r)^2)=3/(1/4)F_(old)=16.56N