In the sequence 123, 148, 173, 198… the value of the common difference, d, is:
25
lf a = –4, b = 5 and c = –3 then a^2 + 2bc evaluates to:
-14
4y^0 + (5y)^0 evaluates to:
5
(x+1)^2 - 4 in factorised form is:
(x+3)(x-1)
In the sequence -16, -9, -2, 5… Find t13
68
Does the point (0,7) lie on the line y = –2x + 7
Yes
/72\ in its most simplified form is:
6/2\
The number that needs to be added to x^2 - 8x in order to complete the square is:
16
Generate the first three terms of the sequence defined by the recurrence relation: t1 = 142, tn+1 = tn + 13
142, 155, 168
The rule for a vertical line passing through the point
(–5, 9) is:
x=-5
2/3\ x 3/7\ is equivalent to:
6/21\
The solutions to
x^2 - 12 = 0 are:
x=-2/3\ and 2/3\
State, correct to two decimal places, the first three terms in the geometric sequence that starts at 143 and increases by 4%.
143, 148.72, 154.67
The gradient of the line joining the points (–2, 1) and (6, –3) is:
-1/2
When the denominator is rationalised,
5/2\ over /3\ becomes:
5/6\ over 3
If the value of the discriminant is less than 0, how many solutions does the equation have?
No solutions
The following recurrence relation can be used to model a compound interest investment of $5450, paying interest at the rate of 3% per annum.
V0 = 5450, Vn+1 = 1.03Vn
What is the investment worth after 9 years (to the nearest dollar)?
$6903.90
Find the equation of the line that is parallel to y = –3x + 5 and passes through (–3, 2).
y = –3x – 7
5^(3/2) in surd form is:
/125\
The value of the discriminant for the equation
2x^2 + 3x -1 = 0
is:
17