500
Solve the equations
3x+4y=17 and 2x+5y=16
Answer:
Graphical method.
Geometrically you could consider these two linear equations are two straight lines. Find the intersection between these two lines by graphing and the point will give the values for x and y.
Substitution method.
3x+4y=17
2x+5y=16
2x+5y=16 Rearrange one of the equations
-2x =-2x to make y the subject
5y=16-2x
/5=/5
y=(16/5 - 2/5x)
3x+4(16/5 -2/5x)=17 Substitute for y in the other
3x+64/5 - 8/5x=17 equation
5*(3x+64/5 - 8/5x=17)
15x +64-8x=85 Solve equation for x
-64=-64
15x-8x=21
7x=21
x=3
3(3) +4y=17
9+4y=17
4y=8
y=2
Solution is x=3, y=2
Elimination method.
3x+4y=17 (1)
2x+5y=16 (2)
Multiply the equation (1) by 2 and (2) by 3
6x+8y=34 (3)
6x+15y=48 (4)
Subtract the equations. (4) -(3)
7y=14
y=2
3x+4(2)=17
3x+8=17
3x=9
x=3
the solution is x=3, y=2