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Derivatives
Tangent line
Trigonometric Applications
Trigonometric identities
Simplifying/ Verifying identities
100
f(x)= x^2 + x - 1
f'(x)= 2x + 1
100
Find the equation of the tangent line to the given curve at the specified point. Y= -3x^2+2x+3; (1,2)
Y= -4x+6
100
Solve the following trig. equation sin Θ+2=0
sin Θ= -2 undefined
100
1+cosx/sinx=cscx+cotx
1/sinx + cosx/sinx or cscx+cotx
100
1+tan^2 x
sec^2 x
200
y= 2x^2 + 3x + 7
4x + 3
200
Find the tangent line at Y= x - 3x^2; (-2, -14)
Y= 13x+12
200
solve the trig equation 2 cosΘ + √3=0
Θ= 7π/6, 5π/6
200
cos^2 y-sin^2 y= 1- 2sin^2 y
1-sin^2 y-sin^2 y or 1-2sin^2 y
200
(sinx)(tanx)(cotx)(cscx)
1
300
y= 8x^7 + 5x^5 + 9x^3
y'= 56x^6 + 25x^4 + 27x^2
300
what is the equation of the tangent line to the given curve at the specified point y=x+ √x; (1,2)
y= 3/2x +1/2
300
tanΘ+3=3 (write tan in terms of sin & cos because there's no tan in the unit circle)
Θ= π, 2/π
300
csc^2 xtan^2 x-1= tan^2 x
tan^2 x +1-1 or tan^2 x
300
(cscx/sinx)-(cotx/tanx)
1
400
y= x^3 - 8x^2
y'= 3x^2 - 16x
400
y=-3√x -x at x=4
y= -1/4x+3
400
3cotΘ- √3=0 (remember to find its reciprocal)
Θ= π/3, 4π/3
400
(secx sinx)/(tanx cotx)=sin^2 x
(sin^2 x cosx)/cosx or sin^2 x
400
(4cosx-3sinx)^2 + (3cosx+4sinx)^2
25
500
y= 4x^6 - 7x^5 - 9x^3
y'= 24x^5 - 35x^4 - 27x^2
500
slope equals zero when... http://cdn-6.analyzemath.com/calculus/Problems/tangent_1.gif
tangent line is a horizontal line.
500
2sin^2Θ-1=0 (remember to square root both sides)
Θ= π/4, 3π4, 5π/4, 7π/4
500
(sin y+ tan y)/ 1+sec y=sin y
sin y(1+sec y)/(1+sec y) or sin y
500
(tanx+cotx)/( csc^2 x)
tanx