What is the vertex of the following equation:
y=(x-4)^2 +6
(4,6)
What is the quadratic formula?
Solve using the complex number system.
x^2+9=0
x= +- 3i
What is the first step to completing the square given this quadratic:
x^2+10x+9=0
Move 9 to the other side
Solve for x:
x^2=4
x=+-2
Does this parabola open up or down:
y=-x^2+6x-9
Down
What does the quadratic formula find?
The zeros or x-intercepts
Solve using complete the square 4x^2+8x+16=0
x=-1+-sqrt3i
x^2+10x + ?=-9+ ?
Fill in the blank (?)
25
2x^2=8
x=+-2
Find the axis of symmetry for the following parabola:
y=-3x^2+6x-2
x=1
Using the quadratic formula find the zeros:
y=x^2-5x+6
x=2 and x=3
x^2 +48=0
Solve using the complex number system
x=+-4isqrt3
Factor the quadratics to complete the square:
x^2+10x+25=16
(x+5)^2=16
5x^2+1=126
x=+-5
Find the y intercept of the following parabola:
y=x^2-4x+3
(0,3)
Or the y intercept is at 3
Solve the equations using the quadratic formula:
y=x^2+9x+20
x=-5 and x=-4
(x-3)^2 +31=7
Solve using the complex number system
x=3+-2isqrt6
What formula helps you complete the square?
(b/2)^2
(3-7i)(3+7i)
58
Find the vertex of the following parabola:
y=x^2-4x+3
Vertex: (2,-1)
DOUBLE POINTS Solve using the quadratic formula:
x^2-4x +(25/4)=0
x=2+-(3i)/2
x^2-12x+44=0
Solve using complete the square
x=6+-2isqrt2
Complete the square:
x^2+4x+?
4
Label this parabola on the coordinate plane. Label the vertex, axis of symmetry, x intercepts, and y intercept.
See whiteboard