4x=24
x=6
3x+18=3
x=-5
Solve for t.
5(t+2)=50
t=8
Solve the inequality
t+4<=9
t<=5
Solve the inequality.
4+3t> -11
t> -5
-6v=30
v=-5
-4r+20=8
r=3
Solve for x.
2(x-1)=30
x=16
x>4
Solve the inequality.
-3n-5>7
n<-4
t/-4=9
t=-36
v/2+4=-2
v=-12
3(c+16)=15
c=-11
-8n<48
n> -6
Solve the inequality.
2y-5<= -15
y<= -5
u/2=-10
u=-20
Subtract both sides by 4
x=2
(x+4)/3=5
x=11
Select ALL that are solutions to the inequality.
w-10>=15
a) w=20
b) w=25
c) w= 30
b) and c)
Solve the inequality.
-1<=8-3t
3<=t
or
t>=3
William walked his dog in the morning and in the afternoon. In the morning, he walks his dog 20 minutes. Altogether, he walks his dog 45 minutes.
How long did William walk his dog in the afternoon?
He walks his dog in the afternoon for 25 minutes
Find the Error. Then identify the correct solution.x
Should add 2 instead of subtract 2 on both sides.
The correct answer is x = 8
Find the Error. Then identify the correct solution.x
-18-3=-21
The correct solution is x=-126
David can spend at most $18 to ride go-karts and play games at the state fair. Suppose the go-karts cost $5.
Write and solve an inequality to determine the amount David can spend on games, if he rides go-karts once. Interpret the solution.
5+x<= 18
x<= 13
The most David can spend games is $13
BOWLING ALLEY A bowling alley charges $5 for shoe rentals plus $10 per game. If Daniella wants to spend at most $45 in total, how many games can she play?
Write an inequality that represents how many games she can play. Interpret the solution.
Let g = the number of games Daniella can play
5+10g<=45
g<=4
This means that Daniella can play at most 4 games with $45.