What is the center,given the equation
(x - 2)2+(y - 5)2 = 9,the center point is..
(2,5)
(y - 3)2 + (x - 1)2 =9, the radius of the circle is..
3
The center is (1,-3) and the radius is 2
(x - 1)2 +(y + 3)2 = 4
Center = (2, 3)
Point = (-1, 4)
(x - 2)2 + (y - 3)2 = 10
Given standard form, rewrite (x + 2)2 + y2 =5 in general form.
x2+ y2 + 4x - 1 = 0
(x - 3)2 +(y - 4)2=25, the center point of this equation is..
(3,4)
(y - 5)2 + (x - 14)2 =16, the radius of the circle is..
4
The center is (2,-1) and the radius is 4..
(x - 2)2 + (y + 1)2 = 16
Endpoint of Diameter = (0, 1)
Endpoint of Diameter = (-2, 5)
(x+1)2 + (y - 3)2 = 5
Given standard form, rewrite (x + 1)2 + (y + 3)2 = 3 in general form.
x2+ y2 + 2x + 6y + 7 = 0
(x - 1)2 + (y - 2)2=9, the center point of the circle is..
(1,2)
(y - 1)2 + (x - 5)2 = 25, the radius of the circle is..
5
The center is (1,-4) and the radius is 3..
(x - 1)2 + (y + 4)2 = 9
Center = (-3, -4)
Point = (-1, 2)
(x + 3)2 + (y + 4)2 = 40
Given x2 + y2 - 2x + 12y +12 = 0 in general form, rewrite in standard form.
(x - 1)2 + (y + 6)2 =25
(x - 2)2 + (y + 5)2 =17, the center point of the circle is..
(2,-5)
x2 + y2 + 10x + 14y + 25=0, the radius of the circle is...
7
The center is (0,3) and the radius is √14
x2 + (y - 3)2 = 14
Center = (3, 0)
Point = (6, -4)
(x - 3)2 + y2 = 25
Given 4x2 + 4y2 - 32x - 40y +120 = 0 in general form, rewrite in standard form.
(x - 4)2 + (y - 5)2 =11
x2 + y2 +16x + 34y + 304 = 0, the center point of the circle is...
(-8,-17)
x2 +(y − 3)2 = 14, the radius of the circle is..
square root of 14
The center is (13,-13) and the radius is 4
(x − 13)2 + (y + 13)2 = 16
Endpoint of Diameter = (-9, 8)
Endpoint of Diameter = (-7, 2)
(x + 8)2 + (y - 5)2 = 298
Given x2 + y2 + 18x - 4y + 36 = 0 in general form, rewrite in standard form.
(x + 9)2 + (y - 2)2 = 49