Evaluating Functions

Function Notation

100

Evaluate f(x) = x + 5, when f(10)

x = 15

200

Evaluate f(x) = 3x - 2, when f(5)

x = 13

300

Evaluate f(x) = 2x - 6, when f(-10)

x = -26

400

Evaluate g(x) = x² + 5, when g(2)

x = 9

500

Evaluate g(x) = x² - 10, when g(-5)

x = 15

Function Fun

100

f(x) = x³ + 4 

g(x) = 2x - 12 

h(x) = x² - 2x + 3 

Evaluate f(1)

5

200

f(x) = x³ + 4 

g(x) = 2x - 12 

h(x) = x² - 2x + 3 

Evaluate g(-2)

-16

300

f(x) = x³ + 4 

g(x) = 2x - 12 

h(x) = x² - 2x + 3

 Evaluate f(-2)

-4

400

f(x) = x³ + 4 

g(x) = 2x - 12 

h(x) = x² - 2x + 3 

Evaluate h(-3)

 18

500

f(x) = x³ + 4 

g(x) = 2x - 12 

h(x) = x² - 2x + 3 

Evaluate f(g(5))

 -4

Solving Functions

100

f(x) = 2x + 11

Solve when x = 11

11

200

f(x) = -4x - 2 Solve when f(x) = -2

x = 6

300

f(x) = x² + 1 Solve when f(x) = 26

f(26)=677

400

g(x) = x² - 10 Solve when g(x) = -2

g(-2)=-6

500

g(x) = x³+ 5 Solve when g(x) = 6

x=1

Functions for Life(calculators needed)

100

Evaluate the value of a car after 5 years. V(t) = 20,000(0.82)^t V(5) =

The value of the car is $7414.80 after 5 years.

200

Evaluate the value of a car after 10 years. V(t) = 30,000(0.82)^t V(10) =

the value of the car is $4123.44 after 10 years.

300

Evaluate the value of a classic car after 5 years. V(t) = 20,000(1.08)^t V(5) =

The value of a classic car appreciates to $29,386.56 after 5 years.

400

Evaluate the value of a classic car after 10 years. V(t) = 20,000(1.08)^t V(10) =

The value of a classic car appreciates to $43,178.50 after 5 years.

500

How much will you have in your bank account in 30 years if you put $100 into it right now, with a 5% interest rate? B(t) = 100(1.05)^t

You will have $432.19.

Fearless Functions

100

Solve f(x) = (x-3)² +5 when x=-3

x = 41

200

Solve f(x) = (x-3)² +4 when x=11

x = 68

300

Solve f(x) = (x-2)³ when x=-10

x = -1728

400

Solve f(x) = (x+5)² - 6 when f(x)=0

x=-6

500

Solve f(x) = (x-3)² + 2 when x=-4

51