Function Notation
f(x) = x + 5,
when f(10)
x = 15
f(x) = x^3 + 4
g(x) = 2x - 12
h(x) = x2 - 2x + 3
f(1)
5
f(x) = 2x + 1
Solve when f(x) = 11
x = 5
Evaluate the value of a car after 5 years.
V(t) = 20,000(0.82)^t
V(5) =
The value of the car is $7414.80 after 5 years.
Solve f(x) = (x-3)2 +5
when f(7)
21
f(x) = 3x - 2,
when f(5)
x = 13
f(x) = x^3 + 4
g(x) = 2x - 12
h(x) = x2 - 2x + 3
g(-2)
-16
f(x) = -4x - 2
Solve when f(x) = -22
x = 5
Evaluate the value of a car after 10 years.
V(t) = 30,000(0.82)^t
V(10) =
the value of the car is $4123.44 after 10 years.
Solve f(x) = (x-3)2 +4
when f(10)
53
f(x) = 2x - 6,
when f(-10)
x = -26
f(x) = x^3 + 4
g(x) = 2x - 12
h(x) = x2 - 2x + 3
f(-2)
-4
f(x) = 5x + 1
Solve when f(x) = 26
5
Evaluate the value of a classic car after 5 years.
V(t) = 20,000(1.08)^t
V(5) =
The value of a classic car appreciates to $29,386.56 after 5 years.
Solve f(x) = (x-2)3
when f(6)
64
g(x) = x2 + 5,
when g(2)
x = 9
f(x) = x^3 + 4
g(x) = 2x - 12
h(x) = x2 - 2x + 3
g(h(3))
0
g(x) = x2 + 1
Solve when g(x) = 10
x=3
Evaluate the value of a classic car after 10 years.
V(t) = 20,000(1.08)^t
V(10) =
The value of a classic car appreciates to $43,178.50 after 5 years.
Solve f(x) = (x+5)2 - 6
when f(1)
30
g(x) = x2 - 10,
when g(-5)
x = 15
f(x) = x^3 + 4
g(x) = 6x - 12
h(x) = x2 - 2x + 3
f(g(3))
220
g(x) = x3 + 5
Solve when g(x) = 32
x = 3
How much will you have in your bank account in 30 years if you put $100 into it right now, with a 5% interest rate?
B(t) = 100(1.05)^t
You will have $432.19.
Solve f(x) = (x-3)2 + 2
when f(a)
(a-3)2 + 2