Probability
Distribution
Confidence Intervals
Hypothesis test
Random
100

Consider a box containing 15 identical pens. It is known that 5 of the 15 pens are defective. Two pens are selected at random, without replacement. What is the mean? (create a probability distribution)

0.689

100

A data set has a normal distribution, a standard deviation of 3.5, and 4% of the data is less than 20. What is the mean?

26.125

100
  1. A local restaurant keeps records of reservations and no shows. In a random sample of 150 Saturday reservations, it is found that 70 of them are no shows.

    1. What is the sample proportion of no shows?

    2. Find a 95% confidence interval for the true proportion of Saturday no shows.

1. 0.4667

2. (0.3868, 0.5465)

100

A pharmaceutical company’s old antacid formula provided relief for 70% of the people who used it. The company tests a new formula to see if it is better and the p-value is calculated to be 0.027. What is the correct conclusion and reason for the conclusion? (use a 0.05 level of significance)

Reject the null hypothesis because the p-value is smaller than the significance level

100

In testing the hypothesis Ho: p=0.3 Ha: p is not equal to 0.3

the test statistic is found to be 2.11. Which of the following is the correct p-value?

0.0348

200

In the last quarter of 2008, a group of 64 mutual funds had a mean return of 2.4% with a standard deviation of 5.6%. Assume the return on the group of funds follows a normal distribution (use the empirical rule) The worst 2.5% will have a return of less than what amount?

-8.8

200

87% of high school students earn a diploma. A random sample of 1600 students are selected. Describe the distribution of proportion.

ṕ ~ AN (0.87, 0.0084)

200
  1. A high school is doing a study on the number of students who actually do their homework. In a random sample of 300 kids, it is found that 100 actually do all of their homework regularly.

    1. What is the sample proportion of students who do their homework?

    2. Find a 90% confidence interval for the true proportion.

1. 0.33

2. (0.2886, 0.3781)

200

A survey was conducted to estimate the proportion of adults who are obese. A 95% confidence interval was calculated to be (0.19, 0.24). Which of the following best interprets the confidence interval?

We can be 95% confident that the population proportion of adults who are obese is between 0.19 and 0.24

200

If we fail to reject a null hypothesis at level of significance (alpha) then the hypothesis test is statistically significant at level (alpha)

true/false

false

300

A mortality rate for certain disease is 25%. A random sample of twelve patients with this disease is selected. What is the probability that exactly half of the patients selected will die from the disease?

.040

300

A data set follows normal distribution and has a mean of 100, a standard deviation of 21. Use the empirical rule. 84% fall above what value?

79

300

What are two ways to get a narrower confidence interval for a proportion?

Increase sample size and decrease confidence level

300

A politician is trying to decide whether to vote for a new tax bill that calls for substantial reforms. He will only vote for the bill if he believes that more than 50% of voters in his district support the bill. A random sample of voters in his district is used to test the following hypotheses: Ho: p = 0.5 vs Ha: p > 0.5 What would be a type II error?

The politician does not believe more than 50% of voters in his district support the bill so he votes against it, and the bill is supported by the majority of voters

300

The power of a hypothesis test is the probability we reject the null hypothesis when the null hypothesis is false

true/false

true


400

A mortality rate for certain disease is 25%. A random sample of twelve patients with this disease is selected. What is the probability that at least two of the twelve patients will die from the disease?

.842

400

A survey was conducted to estimate the proportion of adults who say it is acceptable to check personal email while at work. A 95% confidence interval was calculated to be (0.633, 0.691).

  1. Identify the point estimate of the true proportion 

  2. Identify the margin of error for the above confidence interval

1. 0.662

2. 0.029

400

A researcher wishes to estimate the population proportion of U.S. adults who are overweight. They wish to estimate the proportion to within 4.5 % with a 95% confidence interval. How many U.S. adults should be included in the sample?

475

400

A company’s old antacid formula provided relief for 70% of the people who used it. A hypothesis test whether a new antacid formula is better. The p-value is calculated to be 0.07. Which of the following is the correct conclusion and reason for the conclusion (use a 0.05 level of significance)?

Fail to reject the null hypothesis because the p-value is larger than the significance level of the test

400
  1. Which of the following are true statements?

    1. A small p- value implies strong evidence against the null hypothesis

    2. The p-value is the probability that the null hypothesis is true

    3. If we reject the null hypothesis, it must be false

      1. A only

      2. B only

      3. C only 

      4. A and b are true statements

      5. None of the above are true statements

1

500

The weight of a certain breed of dog follows a normal distribution with a mean of 100 pounds and a standard deviation of 21. What percentage of dogs weigh between 121 and 163 pounds? (use the empirical rule)

15.85

500
  1. A survey was conducted to estimate the proportion of adults who view teaching as a prestigious profession. A 95% confidence interval was calculated to be (0.459,0.521)

    1. Identify the point estimate of the true proportion

    2. Identify the margin of error for the above confidence interval

1. 0.49

2. 0.031

500

A random survey of 375 women found 294 said they change their nail polish once a week. What is a 90% confidence interval for the population proportion?

(0.74, 0.819)

500

A recruiting firm reported that 78% of companies use social networks to recruit job candidates. In a random sample of 220 companies, 81% used social networks for recruiting. Does this provide enough evidence to show that the claim of the recruiting firm is wrong? Identify the null and alternative

Ho: p=0.78

Ha: p not equal to 0.78

500

Data is collected to test the hypotheses Ho: p=0.5 vs Ha: p doesn't equal 0.5. You obtain a p-value of 0.022. Will a 99%, 95%, or 90% confidence interval include the value of 0.5

99%