Variable substitution
5x
x=3
15
b3(bx)=b7
4
x5x7=x35
Multiplied exponents
x12
x4x3x5
x12
(1/3)2
1/9
3+4a
a=-5
-17
(b5)x=b40
8
(24)(34)= 64
Multiplied bases and kept exponents
1,296
x6y9/x5y4
xy5
(7x3y5)2
49x6y10
xy-y
x=3, y=-4
-8
2x = 0.125
-3
43+42=45
Used the multiplication law on addition
80
24+32
25
-8(xy3)0
-8
7y3+2y
y=-2
-60
b3/bx=b9
-6
(5b2)(2b6)= 7b8
Added coefficients, rather than multiplied
10b8
(35)8
340
(x4/2y-3)-5
32/x20y15
a-2ab+b2
a=-3, b=-5
-26
(bx/b6)7=b35
11
(5x2y3z0)4=5x8y24
Didn't apply the exponent 4 to the coefficient
625x8y24
(92)3(94)5
926
(6x7y)(7x3y2)/3x13y3
14/x3