Substitution
5x
x=3
15
b3(bx) = b7
4
x5 x7 = x35
Multiplied exponents
x12
x4 x3 x5
x12
(1/3)2
1/9
3 + 4a
a=-5
-17
(b5)x = b40
8
(24)(34) = 64
Multiplied bases and kept exponents
1,296
x6 y9 / x5 y4
xy5
(7x3y5)2
49x6y10
xy - y
x=3, y=-4
-8
2x = 0.125
-3
43 + 42 = 45
Used the multiplication law on addition
80
24 + 32
25
-8(xy3)0
-8
7y3 + 2y
y=-2
-60
b3 / bx = b9
-6
(5b2)(2b6) = 7b8
Added coefficients, rather than multiplied
10b8
(35)8
340
(x4 / 2y-3)-5
32/x20y15
a - 2ab + b2
a=-3, b=-5
-26
(bx / b6)7 = b35
11
(5x2 y3 z0)4 = 5x8y24
Didn't apply the exponent 4 to the coefficient
625x8y24
(92)3 (94)5
926
(6 x7 y) (7 x3 y2) / 3x13 y3
14/x3