More Practice
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Apartment Hunting
Graphing
Mixed Rules
100

Simplify:

4x^3*5x^2

20x^5

100

[(a^-3b^-3c^-5)/(a^-3b^-3c^8)]^0

1

100

Use the quotient rule for exponents to divide:

(8k^3)/( 4k^6)


2/(k^3)

100

Where is the asymptote for

(1/2)*(1/6)^(x+1) -2


At the line:

y = -2

100

Use the exponent rules to simplify:

(x^3)^2 * x^1


x^7

200

Simplify:

-12k^7 * 4k


-48k^8

200

Use the exponents division rule to solve:

x^m /x^m

x^m-m = x^0 = 1

200

Use the quotient rule for exponents to divide:

(x^2y^5)/(xy^7)

x/(y^2)

200

Where is the asymptote for:

2^(x+2)

y=0

200

Use the exponent rules to simplify:

(3x^2 * 2x^2) / (2x^2)


3x^2

300

Simplify:

(7y^-2x^2)^4


(2401x^8)/(y^8)

300

Simplify:

4x^3*2x^(-3)y^(2)


8y^2

300

Simplify:

(8xy^2)/(2x^6y^2)

4/x^5

300

What should be the first test point for: 

(1/2)*(1/6)^(x+1) -2

First test point:

x = -1

300

Use the exponent rules to simplify:

(4xy^3 * 3x^-4y)^2

Use the exponent rules to simplify:

(144y^8)/(x^6)

400

Simplify:

17dq^3r^2 * 2d^3qr^3


34d^4q^4r^5

400

Simplify:

(12a^(4)b^(2)c^(3))/(4a^(4)bc^(3))

Simplify:

3/b

400

Use the quotient rule for exponents to divide:

(a^-3b^-3c^-5)/(a^-3b^-3c^8)


1 / (a^6bc^3)

400

What is the asymptote AND what should be the first test point for: 

(1/3)^(x+2)


Asymptote at y = 0

First test point x = -2

400

Use the exponent rules to simplify:

(x^3y^4)^3*(3xy^2)^2

9x^11y^16

500

Simplify:

-3y^2(y^2+2y-6)

-3y^4-6y^3+18y^2

500

Finish this proof:

xn = xn -->

xn * 1 = xso

1 = xn / xso

1 = ??????

xn = xn -->

xn * 1 = xn which means

1 = xn / xso, by using exponent division rules

1 = xn-n = x0

500

Use the quotient rule for exponents to divide:

(3x^10y^9)/(8x^4y^4 * 2x^4y^3)


(3x^2y)/(16)

500

Graph:

(1/2)*(1/6)^(x+1) -2

Desmos Picture

Key points: (-1, -1.5), (-2, 1), (0, -23/12)

Asymptote: at y = -2

500

Use the exponent rules to simplify:

(2b^2c^3 * 3bc^5)^3 / (6b^3c^10)


36b^6c^14