Is the following growth or decay: f(x)=100*(0.5)^x
What is decay
100
$1,200 is invested at an annual rate of 3.2%. How much money will the account have after 12 years?
$1751.21
100
Use y = 250(1.2)^t
What is the growth factor?
What is 1.2
100
The population of Baconburg starts off at 20,000, and grows by 13% each year. Write an exponential growth model and find the population after 10 years.
What is f(10) = 20,000(1.13)^10 and population of 67,891
200
Is the following growth or decay: f(x)= 100*(1.4)^x
What is growth
200
The population in the town of Deersburgh is presently 42,500. The town has been growing at a steady rate of 2.7%. What will the population of the town be in 5 years?
Approximately 42, 499 People
200
Use y = 250(1.2)^t
What is the growth rate?
What is 20%
200
The Hippityhoppity bunny decided to have a family reunion at the Magic Forest every 5 years. During the second reunion the family discovered that the number of family members was 154 and was growing at an annual rate of 3.2%.
Write an equation to model the growth of the bunny family.
What is f(x) = 154(1.032)^x
300
Is the following growth or decay: f(x) = 7 (0.94)^x
What is decay
300
The value of a car was $22,000 when it was purchased. They car depreciates at a rate of 19% per year. How much will the car be worth in 8 years?
$4,076.64
300
y = 9.8(1.35)^t
What is the growth factor?
What is 1.35
300
The fish in The Magic Forest Lake were declining at an annual rate at 1.5%. Their current number is estimated at 2500.
Write an equation to model the decreasing number of fish.
What is y = 2500(.985)^x
400
Is the following growth or decay: f(x) = -350 (1.25)^x
What is growth
400
The value of a stock when purchased is $10 a share. However, over the past 5 days the price went down at a constant rate of 4%. How much is the stock worth now?
$8.15
400
y = 9.8(1.35)^t
What is the growth rate?
What is 35%
400
The squid in The Magic Forest Lake were declining at an annual rate at 5.5%. Their current number is estimated at 50,000.
Write an equation to predict the number of squid in the lake in 10 years.