Growth or Decay?
Is the following growth or decay: f(x) = 2x
Growth! Factor is 2.
The population in the town of Huntersville is presently 38,300. The town grows at an annual rate of 1.2%. Write an equation to find the population of the town after 9 years.
y = 38,300(1.012)9
y = 250(1.2)t
What is the initial (or y-intercept)?
$250
Write an exponential growth function to model the situation. A population of 422,000 increases by 12% each year.
f(x) = 422,000(1.12)x
6tv^0
6t
(v^0 = 1)
Is the following growth or decay: f(x)=100*(0.5)x
Decay! Factor is .5
$1,200 is invested at an annual rate of 3.2%. Write an equation to see how much money will the account have after 12 years.
y = 1,200(1.032)12
y = 250(1.2)t
What is the growth factor?
1.2
The population of Baconburg starts off at 20,000, and grows by 13% each year. Write an exponential growth model to find the population after 10 years.
f(10) = 20,000(1.13)10
Simplify: (42)(x-2)
16/x2
Is the following growth or decay: f(x)= 100*(1.4)x
Growth - factor is 1.4
The population in the town of Deersburgh is presently 42,500. The town has been declining at a steady rate of 2.7%. Write an equation to see the population in x years.
y = 42,500(1 - .027)x
or
y = 42,500(0.973)x
y = 250(1.2)t
What is the growth rate?
.2 or 20%
The Hippityhoppity bunny decided to have a family reunion at the Magic Forest every 5 years. During the second reunion the family discovered that the number of family members was 154 and was growing at an annual rate of 3.2%. Write an equation to model the growth of the bunny family.
f(x) = 154(1.032)x
Simplify: 4(x-2)(g3)
4g3 / x2
Is the following growth or decay: f(x) = 7 (0.94)x
Decay. Factor is .94
The value of a car was $22,000 when it was purchased. They car depreciates at a rate of 19% per year. Write an equation showing the value of a car after x years.
y = 22,000(1 - .19)x
or
y = 22,000(.81)x
y = 9.8(1.35)t
What is the growth factor?
1.35
The fish in The Magic Forest Lake were declining at an annual rate at 1.5%. Their current number is estimated at 2500. Write an equation to model the decreasing number of fish.
y = 2500(.985)x
Simplify: ( (4-2)(x-5)(y-9)(z-3) )0
1
Is the following growth or decay: f(x) = -350 (1.25)x
Growth. Factor is 1.25
Reilly invested $400 at 5% interest, compounded monthly. Write and equation to show its value after 10 years.
y = 400(1 + .05/12)120
(120 because 10 years * 12 times a year)
y = 9.8(1.35)t
What is the growth rate?
.35 or 35%
The squid in The Magic Forest Lake were declining at an annual rate at 5.5%. Their current number is estimated at 50,000. Write an equation to predict the number of squid in the lake in 10 years.
f(10) = 50000(.945)10
( (x-2)(y2) ) / ( (b-4)(c4) )
( b4y2 ) / ( c4x2 )