Solving Exponential Functions
Exponent to Log
Log to Exponent
Solving Logarithmic Functions
Common Logs
100

2x = 25

x=5

100

8= 64

log864 = 2

100

log24 = 2

22 = 4

100

log2x = log210

x = 10

100

Given log3=5 and log2=3, what is log15?

log15= 5+3 = 8

200

52x = 520

x = 10

200

172 = 289

log17289 = 2

200

log864 = 2

82 = 64

200

log5x = log2x-9

x = -3

200

Given log2=3 and log5=2, what is the value of log5/2?

log5/2= 3-2 = 1

300

33x = 92x-6

x = 12
300

2561/2 = 16

log25616 = 1/2

300

log5(1/25) = -2

5-2 = 1/25

300

log(-5x-6) = log(x2)

x = -2

x = -3

300

Given log2=3 and log3=4, what is the value of log12?

log12 = (log2)(log2)(log3) = 3+3+4 = 10

400

4x = 82x+5

x = 15/4 OR 3.75

400

(1/6)3 = (1/216)

log(1/6)(1/216) = 3

400

log(1/8)64 = -2

(1/8)-2 = 64

400

log2x-log210 = 2

x = 40

400

Given log3=5, log2=3 and log5=7, what is the value of log(12/5)?

log(12/5) = (log2)(log2)(log3)/(log5) = 5+3+3-7 = 4

500

16x-5 = (1/32)x-6

x = -5

500

64-1/2 = 1/8

log64(1/8) = -1/2

500

log100 = 2

102 = 100

500

2log54+log5x = 3

125/16 OR 7.8125

500

Given log2=5 and log3=2, is it possible to find the value of log42?

No