Simplify
Distributive Property
Substitution
Evaluate
True Equations
100

3x + 5x

8x

100

3(5 + 4)

27

100

3x + 2x

x=4

20

100

4a x 6a 

24a

100

a + 23.50 = 500

a=

a= 476.5


200

10y + 3y +2x

13y + 2x

200

10(x + 5)

10x + 50

200

12x + 4y

Y=7

12x + 28

200

4 x 3 + 22 - 5

11


2x2=4

4x3=12

12+4-5

200

g + 83.78 = 740.32

g=

g= 656.54

300

8a + 4a +5b +3a

15a + 5b
300

12(2a +3b) 

24a + 36b

300

8a + 11b - 3a

a=3

15 + 11b

300

52 - 23 + 3

20

5x5=25

2x2x2=8

25-8+3

300

f + 72.46 = 389.20

f=

f= 316.74

400

a2 x a2

a4

400

3(11x + 12f)

33x + 36f

400

3(4 + 6) + x3

x=2

38

400

32 + 24 - 4 x 5

5


3x3=9

2x2x2x2=16

4x5=20

9+16-20

400

41.39 + c = 374.21

c=

c=332.82

500

24 + 23

27
500

6(3a +2b) +6b

18a + 18b

500

67 - p2 + 21 / 7

p=5

45

5x5=25

21/7=3

67 - 25 + 3 =45

500

72 - 24 + 3 x 5

48

7x7=49

2x2x2x2=16

3x5=15

49-16+15

500

z + 23.122 = 276.56

z=

z=253.438