FACTORING

Factoring GCF

Factoring Trinomials
ax^2 + bx +c

Difference of Squares (Factoring Binomials)

Factoring Word Problems

100

a²-a

a(a-1)

100

x²-x-2

(x+1)(x-2)

100

h²- 9

(h-3)(h+3)

100

A rectangle has the area of x²−11x+18. Identify the expressions that describe the perimeter of a rectangle?

x²−11x+18

(x-9)+(x-2)+(x-9)+(x-2)

4x -22

200

6m - 36n

6(m-6n)

200

k² -7k +12

(k-3)(k-4)

200

c²- 81

(c-9)(c+9)

200

BK Builders, wants to know the perimeter of an entire lot to build a home. The lot has an area of v²+13v+40. Using what you know identify the expressions for the perimeter of the entire lot.

v²+13v+40

(v+5)+(v+8)+(v+5)+(v+8)

4v+26

300

4k²+28k

4k(k+7)

300

a² -6a -27

(a-9)(a+3)

300

z² - 121

(z-11)(z+11)

300

The length of a rectangle is 8 more then the width. Its area is 240 ft sq. Write an equation for its area letting x be the width. Then solve for x and also find the length & factor. (hint: use the visual as a guide & the total area)

______x+8_______

l l

x l

l________________l

240 = x(x+8)

240 = x²+8x

0= x²+8x-240

(x-12)+(x+20)+(x-12)+(x+20)

4x+16

400

4v²n⁴+8vn³+10n²

2n²(2v²n²+4vn+5)

400

p² +17p+72

(p+9)(p+8)

400

x² - 225

(x-15)(x+15)

400

Anne Flower shop is constructing a new garden. They purchased a new garden box and are unable to read the instructions due to them being to small. However they wanted to expand the instructions to the expression is y²-25y+154 where y represents feet. Find length & width of the expanded expression. Then use the length & width and create an expression that sums the perimeter if the box.

y²-24y+154

Length: (y-11) Width: (y-14)

Perimeter: 4y-50

500

6x²y+14xy²-42xy-2x²y²

2xy(3x+7y-21-xy)

500

w²-23w+132

(w-12)(w-11)

500

q² - 400

(q-20)(q+20)

500

Use the 400 Perimeter expression to find the total amount plan if y= 20ft .

Perimeter: 4y-50 y= 20ft

4(20)-50

total ft.= 30