27: 1, 3, 9, 27
GCF = 9
8c (x^2 + 7) + 6 (x^2 + 7)
Answer: (x^2 + 7) (8c + 6)
x^2 + 6x + 5 1*5 = 5/ 1 + 5 = 6
Answer: (x + 1) (x + 5)
2x^2 + 5x + 2 2*2 = 4/ 4 + 1 = 5
(2x^2 + 4x) + (1x + 2)
2x (x + 2) + 1 (x + 2)
Answer: (2x + 1) (x + 2)
x^2 - 36
x * x, 6 * 6
Answer: (x + 6) (x - 6)
Find the GCF of 5x^7 and 25x^4
25x^4 = 1 * 5 * 5 * x * x * x * x
GCF = 5x^4
7b^4 (4b^3 - 8) - 3 (4b^3 - 8)
Answer: (4b^3 - 8) (7b^4 - 3)
x^2 + 14x + 45 45/ 5 + 9 = 14
Answer: (x + 5) (x + 9)
3x^2 + 5x - 2 3*-2 = -6/ 6 - 1 = 5
(3x^2 + 6x) (-1x - 2)
3x (x + 2) -1 (x + 2)
Answer: (3x - 1) (x + 2)
16p^6 - 25g^8
4p^3 * 4p^3, 5g^4 * 5g^4
Answer: (4p^3 + 5g^4) (4p^3 - 5g^4)
35x^3 = 5 * 7 * x * x * x
GCF = 7x^2
7d^2 (5d^5 + 8) - 4 (5d^5 - 6)
Answer: This cannot be factored because the values in both the parenthesis are not the same and do not equal eachother.
x^2 - 7x + 6 6/ -1 - 6 = -7
Answer: (x - 1) (x - 6)
2b^2 + 15b - 8 2*-8 = -16/ 16 - 1 = 15
(2b^2 + 16b) (-1b - 8)
2b (b + 8) -1 (b + 8)
Answer: (b + 8) (2b - 1)
81p^2 - 7q^2
Answer: No, because 7 is not a perfect square.