x^2+7x+10
(x+5)(x+2)
x^2+11x+28
(x+7)(x+4)
x^2-4x+3
(x-1)(x-3)
x=1 and x=3
What is the formula for the axis of symmetry for quadratics?
-b/(2a)
Find the vertex of
y=x^2+8
(0,8)
x^2-5x+6
(x-2)(x-3)
x^2-2x-15
(x-5)(x+3)
6x^2-x-2
(3x-2)(2x+1)
x=2/3 and x=-1/2
Find the axis of symmetry of this equation
y=x^2-4x+3
x = 2
Find the vertex of
y=x^2-4x+3
(2,-1)
x^2+4x-12
(x+6)(x-2)
2x^2+7x+3
(2x+1)(x+3)
3x^2+14x-5
(3x-1)(x+5)
x=1/3 and x=-5
Find the axis of symmetry of this equation
y=2x^2-12x+7
x = 3
Find the vertex of
y=2x^2-12x+7
(3,-11)
x^2-9x+20
(x-4)(x-5)
3x^2-10x-8
(3x+2)(x-4)
8x^2-10x-3
(4x+1)(2x-3)
x=-1/4 and x=3/2
Find the axis of symmetry of this equation
y=-3x^2-17x-5
x=17/6
Find the vertex of
y=-3x^2+18x-5
(3,22)
x^2-6x-27
(x-9)(x+3)
4x^2+12x+9
(2x+3)^2
7x^2-21x+10
(8x-5)(x-2)
x=5/8 and x=2
Find the axis of symmetry of this equation
y=5x^2+x-9
x=-1/10
Find the vertex of
y=5x^2+20x+6
(-2,-14)