Fractions- adding and subtracting
Add these two fractions together and SIMPLIFY if possible
3/4 + 5/16
7/8 divided by 5/8
7/8 x 8/5 = 56/40 --> 1 and 16/40 --
A welder needs to create a frame using four different sections of steel tubing. The lengths required are 14.25 inches, 22.5 inches, 18.75 inches, and 9 inches. What is the total length of steel tubing needed for the project?
64.5 inches
A specialized bracket is composed of three welded plates. The first plate is 6.35 mm thick, the second is 12.7 mm thick, and the third is 4.5 mm thick. What is the total thickness of the combined bracket assembly IN CENTIMETERS?
23.55 MM ---> 2.355 CM
A welder needs to join three pieces of flat bar to create a custom brace. The pieces measure 5 and 1/2 inches, 3 and 1/4 inches, and 4 and 1/8 cinhes. What is the total length of the material before welding?
12 7/8 inches
A welder needs to cut 6 strips of flat bar, each measuring 3 and 1/2 inches long. What is the total length of the material needed for all 6 strips?
21 inches
0.75
3/4
A blueprint for a small bracket requires a steel plate that is exactly 8 inches long. To prepare the cutting machine which uses metric units, you must convert this to centimeters. What is the length in cm?
20.32
1 inch = 2.54 cm
You are working with a 24 and 3/4 inch piece of stainless steel pipe. If you cut off a section that is 9 and 3/8 inches long, what is the length of the remaining piece? (don't worry about kerf)
15 and 3/8 inches
You have a 12-foot length of square tubing that needs to be cut into equal sections that are each 1 and 1/2 feet. How many sections will you be able to cut from this length?
8 sections
Round to the nearest thousandth of an inch:
14.469835 inches
14.470 inches
A blueprint shows that a small metal tab needs to be 4.5 centimeters long. To be precise with his measuring tool, the welder needs to know the length in millimeters. What is it?
45mm
A blueprint for an aviation component requires a "root gap" (the space between two pieces to be joined) of 3/32" If the welder accidentally increases this gap by another1/16", what is the new total width of the gap?
5/32 of an inch
A small welding project requires a piece of plate steel that is 8 and 3/4 inches wide. If you need to build a larger version that is exactly 2 and 1/2 times that width, how wide should the new piece be?
21 and 7/8 inches
RACE:
Convert to a decimal
5/6
0.833
You measure a workbench and find it is 200 centimeters long. How many meters long is the workbench?
2 meters
A machinist’s specification for a mounting plate requires a total width of 12 and 15/16 inches. After a welding pass causes the metal to contract (shrink), the piece now measures 11 and 7/8 inches. How much width did the plate lose due to heat shrinkage?
7/16 of an inch
A specialized weld specification for a heavy-duty T-joint requires a base plate thickness of 7/8 of an inch. To determine the total width of the heat-affected zone, the technician must triple that base plate measurement. Finally, to account for the root opening and a backing strip, the technician must increase that total by exactly 5/16 of an inch. What is the total layout width required?
2 and 5/16"
A blueprint specifies a total length of 78.125 inches for a finished assembly. After welding the components together, the actual measured length is 78.450 inches. By how many inches does the finished piece exceed the blueprint specification?
0.325 inches
You are working with an imported set of welding electrodes that are labeled as 3.2 mm in diameter. To ensure you are using the correct equipment settings in inches, convert this diameter to the nearest fraction of an inch.
1/8 of an inch