Trig
Vectors
Projectile Concepts
Horizontal Projectile Calculation
Angled Projectile Calculation
100

You have the lengths of two sides in a triangle and need to find the length third side. What are you going to use to find it?

Pythagorean theorem

100

A hiker walks south then west. What is the direction of their displacement?

W of S

100

A lemming runs at 10 m/s off of a 5 m cliff side. What is their displacement as they hit the ground?

-10 m

100

A pirate runs at 3 m/s horizontally off the plank and hits the water 1.2 seconds later. How far away from the ship does the pirate hit the water?

3.6 m

100

When playing corn hole, you throw the beanbag with a horizontal velocity of 4 m/s and it remains in the air for 2 seconds. How far away from you does the bean bag land?

8 m

200

You have the magnitude of an angle and the length of a side opposite the angle. What are you going to use to find the length of the adjacent side? Be specific!

Tangent

200

True or False: Hiker A walks 1 km east, then 2 km north. Hiker B walks 2 km north, then 1 km east. Both hikers will end at the same location

True

200

What launch angle causes the projectile to fly furthest down the field?

45°

200

A pirate runs at 3 m/s horizontally off the plank which sits 12 m above the water. How long does it take the pirate to hit the water?

1.56 s

200

When playing corn hole, you throw the beanbag at an angle of 50° with a velocity of 6 m/s. Calculate the beanbag's initial velocity in both the x and y direction.

vx = 6cos50 = 3.86 m/s

vy = 6sin50 = 4.60 m/s

300

You have the length of a side adjacent to an angle and the length of the hypotenuse. What will you use to find the magnitude of the angle? Be specific!

Inverse cosine

300

Name 3 types of vector quantities

Displacement, Velocity, Acceleration, Force

300

A lemming runs at 10 m/s off of a 5 m cliff side. What is their velocity in the y direction just as they leave the cliff?

0 m/s

300

A pirate runs at 3 m/s horizontally off the plank which sits 12 m above the water. What is the pirate's velocity in the y direction after 1.2 seconds?

11.77 m/s

300

When playing a game of corn hole, you throw the beanbag with an initial x velocity of 4 m/s and an initial y velocity of 5 m/s. Calculate the velocity in the y direction of the beanbag after 0.7 seconds

vfy = viy + at = 5 + (-9.81x0.7)

vfy = -1.87 m/s

400

Find the missing angle
                  /|
               / x|
            /      |  17
        /          |
    /              |
/__________|
       16

43.26°

400

A boat sails at an angle of 40° N of W for 25 miles. Calculate how far they sailed in the x and y directions. Don't forget units and direction on your answer.

x: 19.15 mi W

y: 16.07 mi N

400

What is the acceleration of an angle launched projectile at the (a) base of its launch, (b) maximum height, and (c) bottom of its path? (You should have 3 numbers)

(a) -9.81 m/s2

(b) -9.81 m/s2

(b) -9.81 m/s2

400

A pirate runs at 2 m/s horizontally off the plank and hits the water 0.75 seconds later. How high above the waterline was the plank?

2.76 m

400

When playing a game of corn hole, you throw the beanbag with an initial x velocity of 4 m/s and an initial y velocity of 5 m/s. Calculate the time it takes the beanbag to reach the other corn hole board.

tup = 0-5/9.81 = 0.51 s

tair = 2(0.51) = 1.02 s

500

Calculate the missing side
|\
| \
|40\
|     \  x
|       \
|         \
|______\
      6

9.33

500

A hiker walks 10 m west then 5 m south. Calculate the magnitude and angle of displacement. Don't forget unit and direction with your answer

11.18 m at 26.57° S of W

500

You shoot off a cannon at an angle of 35° and it lands 100 yds down a field. What other angle could you shoot off the cannon to have it land at the same point?

55°

500

A pirate runs at 3 m/s horizontally off the plank which sits 12 m above the water. What is the pirates velocity in the y direction as they hit the water?

t = sqrt(2x-12/-9.81) = 1.56 s

vfy = 0 + -9.81 x 1.56

vfy = -15.34 m/s

500

When playing a game of corn hole, you throw the beanbag wit an initial x velocity of 4 m/s and an initial y velocity of 5 m/s. If it takes the beanbag 0.51 s to reach the top of its path, how high off the ground does it get?

y = viyt + 1/2at2 = (5)(0.51) + (0.5)(-9.81)(0.512)

y = 1.27 m