defs.
what must the values of p and q(true or false) be for the conjunction of p and q to be true?
the conjuction is p and q, which means both p and q must be TRUE for p and q to be true!
This is given first order or precedence in ¬p∨q∧r
the negation
negate the value of x is not 7
the value of x is 7
q if p is the same as
p -> q
if 10 is odd, then apples are red
classic p -> q since p is false whole thing will automatically be true !!
Saxons are
LIARS :/
Translate to prop logic : i am happy only when you are not.
only when = implies therefore
if i am happy u are unhappy
p-> not q + always mention p and q
p V not p is a
tautology
if p and q are bi-conditional and they both are false ; p<->q is
true ! This is the if and only if
the opposite of a tautology is
a contradiction ... ( something that is always false)
in
you will succeed if you dont run .
what is the necessary condition :p
in p-> q ; q is the necessary condition hence in this not running is the nessary condition
if p->q is false, the contrapositive is
*Contrapositive will always have the same value and hence is logically equivalent
if something is logically equivalent, it is also a _____________and to prove the following we must ____________
a tautology!
Prove always true using a truth table
simplify : ¬[p∨¬(p∧q)]
is the opposite of p-> q its inverse or converse
+ are inverse and converse logially equivalent ?
inverse and yes !