f(x)=2x-2
Find f(7).
=12
What is the domain and range of the inverse function of: ![]()
Domain: {3, 5, 7, 9, 11}
Range: {1, 2, 3, 4, 5}
True or False: f(x)=x2+4x+3 is a one-to-one function.
False
What is the domain and range of the function?

Range: [0, ∞ )
Domain: (-∞ , ∞ )
Given: f(x)=x2-6x-27 and g(x)=x-9, Find (f-g)(x).
(f-g)(x)=x2-7x-18
If f(x)= 3x2-12
Find f(-4).
36
Will the inverse of this function also be a function? Why or why not?
No, the inverse will not be a function because there will be an input with multiple outputs.
How would you restrict the domain of the function to make it a one-to-one function.

f(x)=x2
Domain: [0, ∞]
Range: [0, ∞]
CC
what is the domain and range of the table?
![]()
domain: [1,5]
range: [3,11]
Given: f(x)=x2-5x-24 and g(x)=x-8, Find (fg)(5).
(fg)(5)=72
What is (f -1+f)(-1)?
-4
If f(5) = -8, what point must lie on the graph of this function's inverse?
(-8, 5)
True or false. The following relation is not a one-to-one function.
![]()
False!
What is the domain and range of y=-3x+4?
All Real Numbers
Given: f(x)=-1-5x2 and g(x)=12, find the value of (f+g)(-3/5).
(f+g)(-3/5)=46/5
Given f(x)=2x2+3x-12 and g(x)=x-5, find f(g(x)).
f(g(x))=2x2-17x+23
Given f(x) = (2/3)x-2
Find f⁻¹(2).
f⁻¹(2) = 6
Find the inverse of the function:
f(x)=|2x+4|-3
f-1(x)= (x+1)/(-2)
Which of the following values of x would not be in the function y = √(x+6)
a.) -4
b.) -7
c.) 4
d.) -6
b.) -7
Given: f(x)=x2+6x+9 and g(x)=x2-9, Find (g/f)(x).
(g/f)(x)= (x-3)/(x+3)
Find f(g(x)) when f(x) = x2 and g(x) = (x+2)/(x-3).
(x+2)2/(x-3)2
Given g(x) = (x+3)/(x-2)
Find the inverse when x=4.
11/3
Find the inverse of the function:
f(x)=2(x-4)2+6
Restrict the domain to make it one-to-one.
f-1(x)=\sqrt((x-6)/2)+4
Domain: [6, ∞]
Range: [4, ∞]
What value of x would not be in the domain of the function defined by f(x)=(x+4)/(x-4).
x=4
Given the table: Find f-1(g(-5))
x f(x) g(x)
-3 8 -18
7 -12 -12
8 -13 0
-5 -20 -3
-16 -3 7
f-1(g(-5))=-16