find the composite of these two functions
f 0 g (1)
f(x) = x+ x^2
g(x) = x
2
Find the inverse of y = 2x
f^-1(x)=x/2
find domain
root 2 ( x-1)
[1, + inf)
( 6x^2 - 3x ) ^2 =
36x^4 - 36x^3 + 9x^2
Find the solution of
6x^2 + 5x - 6 = 0
-1.5 , 2/3
if
f(x) = 4x^2-x+1
then f(2x + 1 ) =
f(2x+1) = 16x^2 + 14x +1
Find the inverse
y= 3 root 2 (x)
f^-1(x) =( x2 ) / 9
Find Domain of F 0 G (x)
F(x) = 1 / (x+1)
G(x) = x^2 - 10
R - {-3,3}
find domain
root 2 ( x-1) + root 2 ( x-2 )
[2,inf)
describe transformation
y = 2f(x-4)+3
a =2 VS
h= 4 translation 4 units right
c=3 translation 3 units up
(3/x) - (3/(x-1))
-3/(x(x-1))
f (x) = 10 / ( x+2) - 5 / (x-2)
f(x) = (5x-30)/((x+2)(x-2))
find inverse of
y = 3 + 1/x
f^-1(x) = 1/(x-3)
find the composite of these two functions f 0 g (x)
f(x) = 1/x + 1 /x^2
g(x) = 1/x
f 0 g (x) = x +
x^2
Find domain
y = 1 / (x^2 - 2)
R - {
- root 2 2, root 2 2
}
Find the minimum value ( y )
h(x) = x^2 - 10x + 16
-9
find the maximum value ( y )
h(X) = -2x^2 + 12x + 6
24
The length of a rectangle is 4 meters more than its width. If the area of this rectangle is 5 m^2, then the peremiter of the rectangle is ?
P = 12 cm
F(x) = (x-1)/3 + x/2
and
F^-1(x) = (6x+2)/5
are inverse ?
yes
find the composite of these two functions f 0 g (x)
f(x) = 2/g(x)
g(x) = x + 1
f 0 g (x) = 2 / (x +2 )
Domain
f(x) = root 2(x-4) / (5x-10)
[4,2)U(2,+inf)
In the library there are Math and Physics books. There are 5 more physic books than math books. If the total number of books in the library is 25, how many are math books ?
10
50 % of 14 is what percent of 35 ?
20
Points a,b, c and d are arranged on a line.
Respectively,
if ad =21 Bd= 14, and ac=13, then bc =
bc = 6
Complete the square
F(x) = 2x^2 - 5x + 4
F(x) = 2(x-5/4)^2 + 7/8
Find the inverse of
y = (2x-1)/(2x-5)
f^-1(x) = (5x-1)/(2x-2)
If We have a rectangle, the length is 3 times the width Knowing that the perimeter is 48, find the length
18
The length of a rectangle is 2 meters more than its width. If the area of this rectangle is 24 m^2, then the length of the rectangle is
6
If Ahmad and Bader has 1210 KD. 4/15 of ahmad’s money is equal to 2/5 bader’s money . Whats bader money
484
A square and an equilateral triangle have the same perimiter. The side of the triangle is 2 cm more than that of the square. Find the side of the triangle’s length
x = 8