Gas Law Relationships
ID the variables
Solve It!
?????
100

This law shows an inverse relationship between pressure and volume. 

Boyle's Law

100

Standard temperature in Kelvins

273 K

100

If 22.5 L of nitrogen at 748 mm Hg are compressed to 725 mm Hg at constant temperature. What is the new volume?

23.2 L

100

Which law is needed? 

A container of gas is initially at 0.500 atm and 25 ˚C. What will the pressure be at 125 ˚C? Assume the volume and amount of gas remains constant. 


Gay-Lussac's Law

200
An increase in the temperature of a gas would cause the pressure to ___________________.

Increase 

200

A gas occupies 53.2 L at a pressure of 0.70 atm with a constant temperature. What will be the new volume if the pressure increases to 1.72 atm?  

21.65 L or 21.7 L

200

48.74 degrees Celsius 

321.74  OR 321.89

200

1.58 mL to L using scientific notation! 

1.58 x 10-3 L

300

An increase in temperature will cause the movement of particles to ______________. 

increase

300

Identify each variable: A weather balloon contains 59.5 L of helium at sea level, where the atmospheric pressure is 101.3 kPa. The balloon is released from an altitude of 10,000m  where the pressure is 61.7 kPa. What is the volume of the balloon when it is released?

V2= ?

V1=59.5 L 

P1= 101.3 kPa

P2= 61.7 kPa

300

112 L to mL

112,000 mL

300

What formula is needed for the following problem: 

A sample of SO2 gas has a volume of 1.16 L at a temperature of 296 K. At what temperature will the gas have a volume of 1.25 L?

T2= V2T1 / V1

400

If the volume of a container increases, what will happen to the quantity of the gas? 

Nothing, no change

400

The value of the ideal gas constant needed if pressure is in mm Hg is ____________.

62.36 L * mm Hg / K * mol.

400

Convert 325 K to Celsius

52 o

400

Molar mass of Ga2(SO3)3 

379.6 g/mol

500

In the combined gas law, what is the variable remaining constant? 

Amount of Gas (moles)

500

ID the variables AND solve 

A gas takes up a volume of 17 L at standard pressure with a temperature of 350 K. What is the new volume is the pressure were raised to 2.5 atm and temperature lowered to 290K? 

V1: 17 L 

T1:350 K

P1: 1 atm

P2: 2.5 atm

T2: 290 K 

V2:  ? 8.21L

500

Solve for the unknown variable:

P1 = ?

 V1 = 10 mL 

P2 = 100 kPa 

V2 = 15 mL

150 kPa

500

A gas takes up a volume of 17 L at standard pressure with a temperature of 299 K. What is the new volume if the pressure were raised to 2.5 atm and temperature raised to 350 K?

7.9 L or 8.0 L