Punnett Squares/Probability
Pedigree/Probability
Genotype/Phenotype
100
8. The Punnett square below is missing the genotype for one of the parents. What is the missing genotype?
rr
100
7. Use the pedigree below to answer the following question.
If the genotype for individual I-2 is rr, what is the genotype for individual I-1?
Rr
100
If the dominant trait for hair is brown (B) and the recessive trait is blonde (b). What is the phenotype for the alleles (Bb)
Brown hair
200
What are the Punnett Square Probabilities?
A. 100% heterozygous
B. 50% heterozygous, 50% homozygous dominant
C. 50% heterozygous, 50% homozygous recessive
D. 75% homozygous dominant, 25% homozygous recessive
C. 50% heterozygous, 50% homozygous recessive
200
9. Which Punnett square represents a 50% probability of having homozygous dominant offspring?
a)
b)
c)
C.
200
If the dominant trait for eye color is brown (E) and the recessive trait is blue (b). What is the phenotype for the genotype (bb).
(bb)= blue
300
Two individuals that are heterozygous for curly hair (H) reproduce. Use a Punnett square to determine the probability that their offspring will express (show) the recessive trait of straight hair (h)
25% probability (hh)
300
What is the probability that individual II-2 is homozygous for the dominant trait?
25% probability that this individual is homozygous for the dominant trait (HH)
300
T=tall
t=short
A person who is heterozygous tall has which genotype.
Tt
400
What is the probability of these two parents having a homozygous recessive offspring?
0% probability of homozygous recessive (bb) offspring
400
Based on the information shown in the pedigree, what is the probability of individual II-1 being heterozygous?
Probability of II-1 being heterozygous= 50%
400
T=tall
t=short
A person who is homozygous recessive will be?
tt= short