5 unit Grade 11 University Math Jeopardy by Matthew Neufeld

Trig Functions

100

y=3cos1/4(x-50)

state the amplitude

A = 3

200

y=3cos1/4(x-50)

state the period 

360 / 1/4 = 1440

300

how do you find the amplitude and midline when only given a max and min value

to find amplitude you do |  (max - min) /2

and to find the midline you do | (max + min) /2

400

y = -sin(4x + 28) + 1

state the range, how do you find it

range = 0 ≤ y ≤ 2

to find this you need to use the amplitude and midline numbers that they give you and find the max and min

a = 1 c = 1

500

tan²(x) - sin²(x) = tan²(x)sin²(x)

=

change rs

=[1-cos²(x)]tan²x

=tan²x - cos²x(tan²x)

=tan²(x) - sin²(x)         Ls = Rs

Transformations

100

what is the vertical stretch

g(x) = 2f(x) - 5

vertical stretch bafo 2

200

what is the vertical shift

g(x) = 3f(x) - 8

vertical shift down 8

300

{0. 9), (2, 7), (3, 5), (4, 3)}

is the information provided a function or not

yes

400

list the asymptotes for the following equation

h(x) = 1/(x-4) + 2

Y = 2 

x = 4

500

a function reflected in the x axis, vertical stretch bafo 3, horizontal compression bafo 1/3, horizontal translation 9 units right, vertical shift 4 units down

determine the equation^

y = -3 √3(x-9)  - 4

Exponent Laws

100

8^x3 x 7^x4

⁼

56^x7

200

68^x10 / 17x

=

4^x9

300

(2^x2y)⁶ x 3^x9

⁼

192x¹³y¹⁵

400

(3/8)^-2

⁼

64/9

500

3^-5/ (3^{-4 +} 3^-6)

⁼

3/10

Rational Expressions

100

(3n-4)²

⁼

9n²-24n+16

200

3m^{2 +} 3m -6

= 3(m² + m-2)

= 3(m² + 2m - m -2)

= 3(m+2) x (m-1)

300

9a^{2 -} 100

=

(3a + 10) (3a - 10)

400

25x² + 25x + 100

= 25(x² + x + 4)

500

9x^{2 +} 48x + 60

= 3(3x² + 16x + 20)

= 3(3x² + 10x + 6x + 20)

= 3(3x+10)+(x+2)

Quadratics/Radicals

100

2^x2-22x+48=0

what are the two x values?

x1 = 8 

x2 = 3

200

express the following in simplest form

√40 

= 2√10

300

express the following in simplest form

(2+4√3)(2-4√3)

= - 44

400

will the following function have a max or min value?

 f(x) = 3(x − 1)(x + 5)

= Minimum value

500

Calculate the value of k such that kx² − 4x + k = 0 has one root.

K = +- 2