Standard Form
Find the vertex of the following equation
y=x2-2x-3
(1, -4)
Find the vertex of the equation y=(x-5)2-1
(5,-1)
Are the two equations y = 3x2 - 4x + 3 and
f(x) = 3(x-2)2 - 4 reflected? Why or why not?
No, because they have the same "a" (3). For them to be reflected one needs to be positive and one needs to be negative
Find the vertex and y-intercept of the following equation:
y=3x2-9
Vertex: (0,-9)
Y-Int: (0, -9)
Find the two points immediately NEXT to the vertex
y= -2(x+3)2+2
(-2,0) and (-4,0)
Describe the transformations that are happening to the graph: (Use words like: faces, up/down, shifts, left/right, and narrow/wide)
y = 3/4(x - 7)2 + 1
The graph is facing up, wide, shifted right 7 and up 1
Find 5 points, including the vertex, that are on the graph y= -x2 - 8x - 12
(-6,0)
(-5,3)
(-4,4)
(-3,3)
(-2,0)
Find 5 points, including the vertex, that are on the graph y = 1/2(x - 4)2 + 8
(2, 10)
(3, 8.5)
(4, 8)
(5, 8.5)
(6, 10)
Give me the equation of a graph that has the vertex (-1, 3) and shifts right 4 down 3
y = (x - 3)2
Find the domain and range of the equation
y=x3+2x - 3
Domain: (-inf, inf)
Range: [-4, inf)
Find the Domain and Range of
y = 3(x - 4)2 + 7
D: (-inf,inf)
R: [4,inf)
Find the new equation:
y = -4(x + 12)2 - 6
Reflected and more steep, shifted left 5 and up 2
y = 7(x+17)2 - 4