HARVEY MATH MADNESS!!!!

FACTOR A NOT 1

100

3p² − 2 p − 5

(3p − 5)( p + 1)

200

3n² − 8n + 4

(3n − 2)(n − 2)

300

5n²+ 19n + 12

(5n + 4)(n + 3)

ABS VALUE INEQUALITY

100

|n/4|<3

-12 <n<12

200

|x+5|<9

-14<x<4

300

|-8n|<32

-4<n<4

factoring trinomials

100

b² − 6b + 8

(b − 4)(b − 2)

200

a² − a − 90

(a − 10)(a + 9)

300

p²  + 11 p + 10

( p + 10)( p + 1)

solving q equations by factoring

100

(k + 1)(k − 5) = 0

{−1, 5}

200

(a + 1)(a + 2) = 0

{−1, −2}

300

x²− 11x + 19 = −5

{3, 8}