HTHS Unit 2 Review (ALG 1A)

W

100

#1

Isolate the variable so that it is alone on one side of the equal sign.

200

#5 C - What does (100,58) mean in this situation?

100 adult tickets were sold and 58 student tickets were sold.

300

#6

C

400

#4 A Solve for x

x = - 6y/4 + 9

H

100

9 A

Is 0 a solution to the equation? 50 = 2x + 38

No, x = 6

200

#7 A

$15(shirts) + $10(hats) = $500 ???

300

9 D - Is 0 a solution to the following equation?

8(x + 2) = 2x + 16

Yes (Let's work this one out on the board together)

400

#7 C

(x,y) so for (26,11) 26=x and 11=y. If you read the second part it says x is the number of shirts and y is the number of hats, so this means 26 shirts were sold and 11 hats were sold.

A

100

#5 A

No, (0,220) is not on the line. (0,200) is though. To be a solution it must be on the line.

200

#9 B - Is 0 a solution to the following equation?

16x = 3x

Yes, 16(0) = 3(0)

300

#3 - Must use x and y as your variables

1.50x + 2.50y = 6

400

#7 D

Yes it is a solution because $15(26 shirts) + $10(11 hats) equals exactly $500 of merchandise sold. It becomes 390 + 110 which equals 500.

T

100

#2 - What does it mean for two equations to be equivalent?

They have the same solution. Example:

2x = 10 and 3x = 15 have the solution x = 5

200

#7 B

Also 20 hats b/c 15x20 + 10x20 = $500.

300

9 C - Is 0 a solution to the following equations?

9x - 15 = 9 + 3x

No, x = 4

400

#4 B - Solve for y

y = - 2x/3 + 6

Bonus (Last)

100

You can risk as many points as you'd like for this question - #8

A, D