If/elif/else
What does elif do in an if / elif / else chain, and why does order matter?
elif adds another condition to the same chain; the first True branch runs and the rest are skipped, so order controls which branch “wins.”
Join text and a name stored in student_name
print("Student: " + student_name)
Write a full-question prompt asking for a name.
input("What is your name? ")
Evaluate: 10 + 2 * 3
16
Fix: Print("Hi")
print("Hi")
What Prints:
n = 70
if n < 60:
print("Below 60")
elif n <= 70:
print("60 to 70")
else:
print("Above 70")
60 to 70
Fix: print("Total: $" + total)
print("Total: $" + str(total))
Read an age as an integer
age = int(input("How old are you right now? "))
Average of 84 and 90 with correct parentheses
(84 + 90) / 2
student name = "Ava"
student_name = "Ava"
The Following prints 2 times, why?
temp = 65
if temp <= 69:
print("Cool")
if temp <= 85:
print("Warm")
else:
print("Hot")
Change the second if to elif
score = 95
print("Honor Roll: " + str(score >= 90))
Honor Roll: True
Does this succeed, and what value?
age_text = " 15 "
age = int(age_text)
Succeeds → 15 (leading/trailing spaces are allowed for int())
Evaluate: 7 + 8 % 3 * 2
11 (8 % 3 = 2; 2*2 = 4; 7 + 4 = 11)
What is wrong with this?
avg = 84 + 90
print("Average: " + str(avg) / 2)
print("Average: " + str(avg / 2))
What’s wrong with this grade chain, and how do you fix it
score = 92
if score >= 70:
print("Pass")
elif score >= 90:
print("A")
else:
print("Try again")
The order is wrong—score >= 70 catches 92 first. Put score >= 90 before >= 70.
With g = 10, give one line (no commas) that prints exactly Grade 10/10
print("Grade " + str(g) + "/10") (any equivalent using + and str() is fine)
Ask minutes (int) and seconds (int). Print "Total minutes: " as a decimal (e.g., 1.5 for 1 min 30 s)
m = int(input("How many minutes? "))
s = int(input("How many seconds? "))
print("Total minutes: " + str(m + s/60.0))
If two waters cost $1.50 each and a bar is $2.25, with tax 8.5%, what is the final total rounded to 2 decimals?
round((2*1.50 + 2.25) * 1.085, 2) → 5.70
price = input("What is the price of one snack (e.g., 1.50)? ")
if price <= 2.00:
print("Affordable")
elif price <= 10.00:
print("Pricey")
else:
print("Luxury")
float()
Why will this crash for valid input, and what line should be corrected?
age = input("What is your age in years? ")
if age < 5:
label = "Free"
elif age <= 12:
label = "Child"
elif age <= 64:
label = "Adult"
else:
label = "Senior"
input() returns a string; comparing string to number crashes. Fix first line to
age = int(input("What is your age in years? "))
x = 3
y = 2
msg = "Sum: " + str(x + y)
x = "3"
print(msg)
print("Sum: " + x + str(y))
Sum: 5
Sum: 32
Ask for a nickname. If the user just presses Enter, use "Anonymous". Print Welcome, NAME!
nick = input("What is your nickname? ")
if nick == "":
nick = "Anonymous"
print("Welcome, " + nick + "!")
((25 % 7) * (18 / 3) + 6) / ((14 - 8) + (21 % 4))
30 / 7 ≈ 4.2857142857
adult = int(input("How many adult tickets? "))
student = int(input("How many student tickets? "))
adult_price = input("What is the adult price (e.g., 12.50)? ")
student_price = float(input("What is the student price (e.g., 8.00)? "))
subtotal = adult * adult_price + student * student_price
fee = 2.00
total = subtotal + fee
print("Total: $" + round(total, 2))
adult_price = float(...)