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100

Solve

3x-5leq-4

xleq frac{1}{3}

100

True or False

f(x)=frac{ax+b}{cx+d}

 The above function always has vertical and horizontal asymptotes whenever the values a, b, c and d are not zeros.

TRUE

100

True or False

The reciprocal of a quadratic always features horizontal and vertical asymptotes

FALSE

For the reciprocal of a function like  

f(x)=x^2+3

there are no vertical asymptotes

100

True or False

A rational inequality with 2 x-intercepts and 2 vertical asymptotes will create 4 intervals on the x-axis so long as there are no x-intercepts and vertical asymptotes in common.

FALSE

This will create 5 intervals

100

This is one way in which solving rational equations is different from solving polynomial equations

We have to consider vertical asymptotes (there may be more, we will check all answers)

200

True or False

These are equivalent

-2x+7> 2

x-frac{7}{2}<-1

TRUE

When we multiply or divide by a negative, the direction of the inequality switches.

In this example, we divided by -2 both sides

200

True or False

If a linear function has a negative y-intercept and a negative slope, its reciprocal is always increasing.

TRUE

Increasing and Decreasing behaviours are always opposite. A linear with negative slope is always decreasing.

200

True or False

Whenever the quadratic function is increasing, the reciprocal is positive

FALSE

A reciprocal of a quadratic can be negative and decreasing

200

The solution intervals for the inequality

frac{2x^2+5x-3}{x^2-4}geq0

contain one or more errors.  Find it (them)
Solution intervals:

(-infty,3]U[-2,1/2]U[2,infty)


There are vertical asymptotes at -2 and 2, so any solution that includes them is incorrect.

In the first interval it should read -3, not 3

200

The first step to solve this equation is...

frac{2x^2-6x+3}{x-6}=0

Multiply both sides by the denominator

300

True or False

To solve a polynomial inequality, we do not need to look at the asymptotes, only the x-intercepts

True

Polynomial inequalities do not feature asymptotes 😉

300

Equation of the reciprocal to the function shown here

g(x)=\frac{1}{x-\frac{1}{2}}

300

True or False

The signs of a quadratic and its reciprocal are opposite

FALSE

Signs are always the same

300

Solve

frac{x+2}{x^2-16}leq0

{x<-4}U{-2leqx<4}

(-infty,-4)U[-2,4)



300

Solve 

(2x^2-6x+3}/{x-6}=0

This is not factorable, you need quadratic formula

x= 0.634 and x = 2.366

400

Solve 

x^3+2x^2-3x+5>5

(-3,0) U (1,+infty)

{-3<x<0}U{x>1}

400

Equation for the function shown below

f(x)=\frac{3x-1}{x+2}

400

The equation of the reciprocal of the quadratic with the following characteristics:

x-intercepts at -5 and -2

It opens down

|a| = 3

g(x)=-\frac{1}{3(x+2)(x+5)

400

Solve

frac{2x-1}{5x+3}geq0

(-infty,-3/5)U[1/2,+infty)

{x<-3/5}U{xgeq 1/2}

400

Solve

frac{x^2-3x-18}{x^2-x-6}=0

x = -3 and x = 6

500

Solve

2x^3-3x^2-23x+17<5

(-infty,-3)U(frac{1}{2},4)

{x<-3}U{frac{1}{2}<x<4}

500

Equation of the function with the following characteristics

x-intercept at -0.4

y-intercept at  -frac{2}{3} 

vertical asymptote at    frac{3}{2 

horizontal asymptote at 2.5


g(x)=\frac{5x+2}{2x-3}

500

Create an example of a reciprocal of a quadratic function that has no vertical asymptote and a horizontal asymptote at 3

Many possibilities, here is a simple one

f(x)=frac{1}{x^2+2x+4}+3

500

Solve

frac{2x^2+x-1}{x^2-4x-4}leq0

Interval Solutions

[-1, -0,83) U [0.5, 4.83)

500

Solve

frac{x-3}{10}=4x

x=-1/13