Product Rule of Powers
Quotient Rule of Powers
Negative Exponents
Miscellaneous Power Rules
Properties of Exponents
100
x2 + x4
x6 because we have same bases. Therefore, you add the powers. 2 + 4 is 6.
100
83 /85
The answer is 8-2 because once you set up the fraction as 83-5 you would have to subtract 5 from 3 which would give you -2. Therefore, 83-5 = 8-2
100
5-2
1/52 because you cannot have negative exponents in the numerator. Therefore, you would move the 2 to the denominator, making is positive 2. Now, move the 1 to the numerator (top) and the 5 with a positive power of 2 will be at the denominator (bottom)
100
(x2a/y3b)3
x6a/y9b because broken down, this would actually be x2a*3/y3b*3 . Looking at that fraction, all you would have to do is multiply the powers in each of the same bases. 2 times 3 is 6 and 3 times 3 is 9. Therefore, the answer to the problem would be x6a/y9b .
100
What is 2 to the power of 7?
27=128 because 2*2*2*2*2*2*2 is 4,16,32,64,128!
200
143 + 146
149 because again, same bases means we keep them and just add the powers. 6 + 3 is 9. Therefore, 143+6 is 149 .
200
1007/1002
1007-2 would simplify to 1005 because 7-2 is 5 and with the base of 100, the answer is 1007-2
200
13-9/135
13-9-5 is what this equation would simplify to, which would then be 13-14
200
a4/411
broken down, what the equation really says is a4-11, which would be a-7
200
b0
1; anything to the power of 0 is going to be 1 no matter how big or small the base number is.
300
x4 + x3 + 6x4 + 78x2
86x13 because after combining like terms, or bases, I added the exponents and after adding x+x+6x+78, it's 86 and after adding the powers, or exponents, 4+3+4+2 is 13! Therefore, the answer is 86x13
300
Find the value of:
(5x2y)3/x-5y-3
(5x2y)3/x-5y-3
53x6y3/x-5y-3
53x6-(-5)y3-(-3)
53x6+5y3+3
125x11y6
300
(x-8*33)/(4-2*y2)
(x-8*33)/(4-2*y2)
42*33/x8*y2
16*9/x8y2
432/x8y2
300
z=(3)2 (-5)3
z=(3)2 (-5)3
z=(3)(3)(-5)(-5)(-5)
z=(9)(-125)
z=-1125
300
What is 42 to the third power?
74,088 because 42*42*42 would result in 74,088
400
2208+2133
43311 because 220+213 is 433 and the powers added would give me 11.
400
9(u2+5v)-9u(2u)/(u2+5v)2
9(u2+5v)-9u(2u)/(u2+5v)2
Step 1: Distribute
9u2+45v/(u2+5v)2
400
4a3b5c6d/a-1b-2
4a3b5c6d/a-1b-2
4a3a1b5b2c6d
4a3+1b5+2c6d
FINAL ANSWER!!
4a4b7c6d
400
(4x-4y5)3
64(1/x12)y15
64y15/x12
400
99+70
100
500
472+566+819
18417
Step 1: Add bases
47+56+81=184
Step 2: Add powers
2+6+9=17
Step 3: COMBINE
18417 is the final answer!
500
(5/3)4=54/34
(5/3)4=54/34
625/81
500
(41a5b-3)-3
(41a5b-3)-3
(-4)-3a-15b9
b9/(-4)3a15
FINAL ANSWER!!
=b9/-64a15
500
x2+x+2+(2x2-2x)
x2+x+2+(2x2-2x)
x2+x+2+2x2+(-2x)
3x2+(-x)+2
3x2-x+2
500
(d) x2-7x-8/x2+3x+2