500
An applied force of 20 N is used to accelerate an object to the right across a frictional surface. The object encounters 10 N of friction. Use the diagram to determine the normal force, the net force, the coefficient of friction (μ) between the object and the surface, the mass, and the acceleration of the object. (Neglect air resistance.)
Note: To simplify calculations, an approximated value of g is often used - 10 m/s/s. Answers obtained using this approximation are shown in parenthesis.
Fnorm = 100 N; m = 10.2 kg; Fnet = 10 N, right; "mu" = 0.1; a =0.980 m/s/s, right
( Fnorm = 100 N; m = 10 kg; Fnet = 10 N, right; "mu" = 0.1; a =1 m/s/s, right )
Since there is no vertical acceleration, the normal force is equal to the gravity force.
The mass can be found using the equation Fgrav = m * g.
Using "mu" = Ffrict / Fnorm, "mu" = (10 N) / (100 N) = 0.1.
The Fnet is the vector sum of all the forces: 100 N, up plus 100 N, down equals 0 N. And 20 N, right plus 10 N, left = 10 N, right.
Finally, a = Fnet / m = (10 N) / (10.2 kg) = 0.980 m/s/s.