1
Jaime and Lisa have a combined age of 48. Lisa is three times as old a Jaime.
1. Define variables (or pronumerals) to stand for unknown numbers
Let:
l = Jaime
Katy and Alexia have a combined age of 39. Alexia is half the age of Katy.
1. Define variables (or pronumerals) to stand for unknown numbers
a = Katy
The weight of 8 identical soccer balls is 1500 g.
1. Define variables (or pronumerals) to stand for unknown numbers
Let:
s = weight of one ball in g
Jenny buys 4 cups of coffee for $13.20.
1. Define variables (or pronumerals) to stand for unknown numbers
Let:
c = cost of one cup of coffee
Jaime and Lisa have a combined age of 48. Lisa is three times as old a Jaime.
2. Write an equation to define the problem
l + 3l = 48
Katy and Alexia have a combined age of 39. Alexia is half the age of Katy.
2. Write an equation to define the problem
a + 1/2a = 39
The weight of 8 identical soccer balls is 1500 g.
2. Write an equation to define the problem
8c = 1500
Jenny buys 4 cups of coffee for $13.20.
2. Write an equation to define the problem
4c = $13.20
Jaime and Lisa have a combined age of 48. Lisa is three times as old a Jaime.
3. Solve the equation algebraically if possible to find their ages
l + 3l = 48
4l = 48
l = 12
Therefore, Jaime's age is 12 and Lisa's age is 12 x 3 = 36
Katy and Alexia have a combined age of 39. Alexia is half the age of Katy.
3. Solve the equation algebraically if possible to find their ages
a + 1/2a = 39
1.5a = 39
a = 26
Therefore Katy is 26 and Alexia is 1/2 x 26 = 13
The weight of eight identical soccer balls is 1500 g.
3. Solve the equation algebraically if possible to find the weight of one soccer ball.
8c = 1500
8c/8 = 1500/8
c = 187.5 g
Therefore, the weight of one soccer ball is 187.5 g
Jenny buys 4 cups of coffee for $13.20.
3. Solve the equation algebraically if possible to find the cost of one cup of coffee
4c = $13.20
4c/4 = $13.20/4
c = $3.30
Therefore, one cup of coffee costs $3.30.