What is the slope of a horizontal line?
m = 0
y = -3x – 6
Does this line have positive, negative, zero or undefined slope?
Negative
(The slope is -3)
Name the slope of the line and a solution point:
y + 3 = 6(x – 5)
m = 6
(5, -3)
Write the equation in standard form:
y = -2x -6
2x + y = -6
Write the equation of the line parallel to
y=-17/5
And passing through the point (8, 0)
y=0
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What form of linear equation should you use to model this situation?
Standard Form
What is the slope of a vertical line?
m is undefined
Write the equation of the line with slope of
and passing through the point (0, 17)
y=1/3x+17
Write the point-slope equation of the line passing through the points (2, 4) and (7, 5).
y – 4 =1/5(x – 2)
OR y – 5 = 1/5(x – 7)
Write the equation in standard form:
y-5=1/5(x+10)
x – 5y = -35
Write the equation of the line perpendicular to
y=3/4
And passing through the point (16, 99)
x=16
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Write the equation in standard form.
x+2y=10
y=5
Horizontal or Vertical?
Horizontal
Write the equation of the line with slope of -5
and passing through the point
(1/3, 4/3)
y = -5x + 3
Write the point-slope equation of the line passing through the points (-2, 4) and (7, -5).
y – 3 = 2x
Write the equation in standard form:
y + 3 =3/2(x - 8)
3x – 2y = 30
Write the equation of the line parallel to
y = -4/7 x + 14
And passing through the point (21, 2)
y=-4/7x+14
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What form of linear equation should you use to model the situation?
Slope-Intercept Form
x = 1
Horizontal or Vertical?
Vertical
Write the equation of the line passing through the points (6, 0) and (3, -4).
y=4/3x-8
Convert the slope-intercept equation to point-slope form:
y = 2x + 3
y – 3 = 2x
Write the equation in standard form:

x – 2y = 4
Write the equation of the line perpendicular to
y - 6 = -2(x + 9)
and passing through the point (8, 5)
y = 1/2x + 1
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Write the equation in slope-intercept form.
y=20x+100
What is the slope of the line passing through points
(3, -1) and (3, 9)?
Undefined
Write the equation of the line:

y=5/7x-9
Write the equation of the line in point-slope form: 
y = 1/4(x + 6)
y - 1 = 1/4(x + 2)
Put the equation in standard form:
-x-1/4y+3=-2/5
20x + 5y = 52
Write the equation of the line perpendicular to
the x-axis and passing through the point (88, 2)
x=88
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Write the equation in point-slope form. Do not simplify.
y-100 = 20(x-0)