x+5<12
x<7
−2x>6
x<−3
x+3<10
x<7
Final answer: x>7
Final inequality sign is reversed incorrectly
True or False:
If x>3, then 2x>6
True
Solve: 4x+3<2x+11
x<4
3x>15
x>5
−x/3≤4
x≥−12
−2x>8
x>−4
Forgot to flip the inequality sign
Which is greater:
All solutions of x<−2 OR all solutions of x>−2?
x>-2
Solve: 3(2x−1)≥5x+4
x≥7
2x−7≤9
x≤8
−4x+5>13
x<−2
3x−6≤9
3x≤3
x≤1
Computation error: x≤5
True or False:
Multiplying both sides of an inequality by a negative number keeps the sign the same.
False, it flips the sign
Solve the compound inequality:
2<x+1≤7
1<x≤6
5−2x>1
x<2
−2(x−3)≤8
x≥−1
−x+4<1
−x<−3
x<3
Did not flip inequality after multiplying by −1
If x≤5, is x=5 a solution? Explain briefly.
Yes
Solve:
(x-2)/3+4>6
x>8
3(x−4)≤2x+5
x≤17
(−3x+6)/(-2)>4
x>14/3
x+1>2x+5
-4>x
the minimum integer value of x is -3
x=-3 is max. integer value
Which inequality represents:
“All numbers between 2 and 6, including 2 but not 6”?
2≤x<6
Create your own inequality that has the solution:
x>3
(Any valid inequality is acceptable)
Example: x−1>2 (answers may vary)