LOGARITHMS - AHMAD & OSAMA

Find the value of:

100

Log₂16=

4

200

Log₅25=

2

300

Log₁₀1000=

3

400

Log₅1/5

-1

500

Log₃₂3√32

3/2

logarithmic equation

100

y=4^x

Log₄y=x

200

y=9^x

Log₉y=x

300

y=√ 3^x

Log_√3 y=x

400

y=3²ⁿ

Log₃ y=2n

500

y=5^x/2

2Log₅y=x

Exponential equation

100

y=Log₇x

7^y=x

200

y=Log₃x

3^y=x

300

y=Log₅2

5^y=2

400

y=Log₁₀₀ x

100^y=x

500

y=Log₃₀₀₀ x

3000^y=x

INVERSE FUNCTION

100

F(X)=4^x

Log₄x=F^-1(x)

200

F(x)=10^x

Log₁₀x=f^-1(x)

300

F(x)=Log₇ x

7^x=F^-1(x)

400

F(x)=Log_√2 x

√2^X=F^-1(x)

500

F(x)=5 Log₃y

3^x/5=F^-1(x)

TRUE OR FALSE

100

Log₇(3√7) is equal to 7^1/2

FALSE

Correct answer= 7^1/3

200

Log₂ 8=3 is equal to 2⁸=3

FALSE:

Correct answer= 2³=8

300

 10⁴=10000 is equal to Log₁₀10000=5

False

Correct answer= Log₁₀10000=4

400

is Log₅125=3

TRUE

500

is Log_ax asymptotic to the Y axis

TRUE