Simplifying Log Expressions
Solving Log Equations
Solving Exponential Equations
Word Problems
Log to Exponential, Exponential to Log
100

Write as a Single Log: Log3(x) + Log3(4)

Log3(4x)

100

Log2(x) = Log2(6)

x = 6 

100

2x = 32

x = 5

100

If my $1 investment grows 50% each day, how long will it take my investment to grow to $50? (Round to nearest tenth)

9.6 days 

100

Rewrite the following in exponential form: Log2(x) = 3

2= x 

or x = 23

200
Write as a Single Log: Log4(a) - Log4(b) + Log4(c)

Log4(ac/b) 

200

Log2(2) + Log9(x) = 1 

x = 1

200

32n + 4 = 18

(Round to nearest thousandth) 

n = 1.201

200

If a $10000 car depreciates 5% per year, how long will it take for the car to be worth $8000? (Round to nearest tenth)

4.4 years 

200

Rewrite the following in Log Form: 1.04t = 5

t = Log1.04(5)

300

Write as a single log, then evaluate: 

Log4(80) - Log4(5)

Log4(16) = 2 

300

3 + Log4(2x - 3) + 2 = 5 

x = 2

300

42w - 7 - 5 = 11

w = 4.5 

300

A population of 4 bacteria doubles every hour. How long will it take the bacteria to grow to 4096? 

10 hours 

300

Rewrite the following in Log Form: 3n + 2 = 18 

Log3(18) = n + 2 

400

Simplify by hand: Log3(54) - Log3(2) + 2Log3(3)

5

400

Log3(x + 1) + Log3(4) = Log3(8)

x = 1

400

3ex - 1 - 8 = 20

(Round to the nearest hundredth)

x = 3.23

400

A population of deer starts at 50 and grows 8% per year. How many months will it take the population to grow to 70? (Round to the nearest whole number) 

52 months

400

Write in Exponential Form AND solve for x: 

Log2(x + 7) = 3

23 = x + 7 

x = 1

500

Write as a Single Log: 3Log2(3) - Log2(9) + Log2(5)

Log2(15)

500

Log2(x) + Log2(x + 2) = 3 

x = 2 

500

5p(52p + 1) = 125

p = 2/3

500

A population of 2 bacteria triples every 6 hours. How long will it take for the bacteria to reach a population of 200? (Round to the nearest whole) 

25 hours 

500

Simplify the expression as much as possible by hand: 

Log2(8) + Log3(3) - Log4(1) 

3 + 1 - 0 = 4