Show:
mA-Z
you do the mAth
mA-morphosis
noise? I don't know her
the exposure zone
100

mAs is the primary factor controlling...

quantity 

100

50 mA for 0.012 seconds = _____mAs

0.6 mAs

100

3/4 sec = ______ sec in decimal form

0.75 sec

100

insufficient mAs can result in an image with what

quantum mottle

100

when mAs is doubled, what happens to the spectrum emission curve

the amplitude doubles

200

what 2 qualities are image quality broken into?

photograpghic properties (visibility)
geometric properties (recognizability)

200

500 mA at ______ msec = 250 mAs

500 msec

200

You accidentally select 0.02 sec at 300 mA. What mAs will be delivered?

300 mA × 0.02 s = 6 mAs

200

mAs must be increased/decreased by __________ to be visible to the human eye

25-35%

200

how does increasing mAs affect patient dose

increases dose

300

unit of measurement of tube current

ampere (amp)
mA= 1/1000 amp

300

100mA at .2sec will produce the same exposure as _____ mA at 0.05sec

800 mA

300

A technique uses 20 mAs at 100 mA. What exposure time is needed?

Time = 20 mAs ÷ 100 mA = 0.20 s.

300

how to eliminate quantum mottle from an image

increase mAs

300

what effect will cutting the mAs in half on the resulting IR exposure 

half the exposure intensity 

400

formulas
mAs=
time=
mA=

mA x time
mAs/ mA
mAs/ time

400

_____mA at .2sec will double the exposure intensity produced by 200mA at 0.05sec

100mA

400

Your patient moved on the first exposure: 25 mAs at 0.25 sec. You want to shorten time to 0.1 sec. What new mA maintains the same mAs?

New mA = 25 mAs ÷ 0.10 s = 250 mA.

400

digital processing allows for ________ of inaccurate mAs selection

correction
-computer re scales exposure intensity and contrast

400

mAs and exposure intensity are ________ proportional

directly


500

describe two situations where a short exposure time would be advantageous

pt is unable to cooperate
breathing is erratic

500

480mA at _____sec will produce half the exposure intensity of 800mA at 0.003sec

0.0025 sec

500

The technique chart calls for 8 mAs. If your only time options are 0.01, 0.02, and 0.04 sec, what mA settings would work?

  1. Options to get 8 mAs:

  • 0.01 s → 8 ÷ 0.01 = 800 mA

  • 0.02 s → 8 ÷ 0.02 = 400 mA

  • 0.04 s → 8 ÷ 0.04 = 200 mA

500

law of reciprocity 

any combination of mA and time that equals the same mAs, will produce the same intensity (density)

500

what machines use s numbers

fuji