Distance & Midpoint
Segment & Angle Addition
Transformations
More Transformations
Congruent Figures
100
Find the distance between the two points. Simplify radical if possible and give approximation to one decimal.
2sqrt13
7.2
100
If DF bisects angle EFG, find angle EFG.
124º
100
Triangle ABC is translated based on the vector shown. Write the coordinates of A'.
A'(-1, 1)
100
Write a vector that maps the given pre-image to the image.
< 8 , 4 >
100
EFGH = NPLM, Find x
x = 11/2 or 5.5 m
200
Find the midpoint between (-5, 6) & (9, 0)
M(2, 3)
200
Solve for x
x = 13
200
Complete the motion rule that would describe a reflection over the y-axis.
(x,y) →
(x,y) → (-x,y)
200
List the points for the image reflected across the line y=x. A(4,-8) B(6,5) C(7,-2) D(-4,-9)
A'(-8,4) B'(5,6) C'(-2,7) D'(-9,-4)
200
EFGH = NPLM, Find y
y = 9
300
Find the distance between the two points. Simplify radical if possible and give approximation to one decimal.
A(-5,4) B(4,-9)
5sqrt10
15.8
300
Use the Angle Addition Postulate to find the value of x. (A straight line is 180º)
2x + 15 +13x + 30 + 90 = 180
x = 3
300
Triangle ABC has coordinate points A(-2, -2), B(1, 4) and C(-2, 5). Graph the pre-image and the image of the triangle after translating along ⟨-2, 3⟩. Label both figures and list the coordinates of the image.
A'(-4, 1), B'(-1, 7), C'(-4, 8)
300
Rotate the following figure 180º. List the points of the image.
D'(3,-1)
E'(1,1)
F'(1,4)
G'(3,3)
400
If the line segment AB has an endpoint A(-5, 2) and a midpoint of M(3,0). Find the other endpoint, B.
B(11, -2)
400
BD = 12
400
State the motion rule for the following transformation:
(x,y) → (-y,x)
400
_______ is the result of A translated down and left, reflected over a vertical line, and rotated 180º.
B
500
Find A', B', C', A", B", C" given the motion rule
A(3,4) B(-7,2) C(-3,-4)
(x,y) → (-x,y) → (2y, x)
A'(-3,4)
B'(7,2)
C'(3,-4)
A"(8,-3)
B"(4,7)
C"(-8,3)
500
Line segment LS has endpoint L(-4,5) and S(6,-2). The segment is first reflected over the y-axis, then translated with the vector <-4,9>. Lastly, the segment is rotated 180º. What is the final location of S"'.
S"'(10,-7)