3 variables
2 variables
1 variable
find x
word problems
100

x+y=5

y+z=6

z+x=9

x=4

y=1

z=5

100

4x+5y=5

4x-5y=-5

x=0 y=-1

100

4x-6=-2

x=1

100

-x+1=a

x=-a+1

100

each bag of candy weighs 160g.

if the total weight of all the bags is 1280g.how many bags all together?

8 bags
200

x+y=6

y+z=-5

z+x=7

x=9

y=-3

z=-2

200

x+2y=7

4x-2y=18

x=5

y=1

200

2.5x+4=9

x=2

200

-3x-b=a

x=a+b/3

200

there are 5 boxes of chocolates which weigh 80g each and some bags of candy which weigh 140g each. If they weigh 1660g altogether, how many bags of candy are there?

9 bags

300

3x-2y=7

7y-z=10

2x-5y+z=-2

x=3

y=1

z=-3

300

x+y=-10

x-y=6

x=-2

y=-8

300

4x-2=5x

x=-2

300

3x-a/4=b

x=a+4b/3

300
There are 7 boxes of chocolates in a bag which weigh 1000g altogether. If the weight of the bag is 20g,how many grams does each box of chocolates weigh?

140g

400

2x-2y-z=3

4x+4y-z=15

4x+6y=18

x=3

y=1

z=1

400

6x+8y=38

6x-8y=22


x=5

y=1

400

x+9=2x+6

x=3

400

3(x-b)=a

x=a+3b/3

400

x times 3 equals 4

x=4/3

500

x+y-z+w=10

x+3y-4z+5w=26

x+4y-7y+7w=37

x+2y-3z+6w=22

x=4

y=-9

z=-2

w=-2

500

wow

w2o

500

garganta

g2a3r1t1n1

500

b/3+c=a

solve b

b=3a-c

500

If 5 is added to x times 3, this equals x times 5 with 7 subtracted from it.

x=6